Area of sector is 17.584 meters
<em><u>Solution:</u></em>
Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m
Diameter = 12 m
Radius = Diameter / 2 = 6 m
An angle of 56 degrees is the fraction 
of the whole rotation
A sector of a circle with a sector angle of 56 degrees is therefore also the fraction of the circle
The area of the sector will therefore also be of the area
Thus area of sector is 17.584 meters
Answer: m = ½
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This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
