12^3 = 1728; 14^3 = 2744;
Answer:
Step-by-step explanation:
Part A:
C = 10t + s
Part B:
10(3) + 8
30 + 8 = $38
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
To solve 7-2a-5-14=-2+3a :
1) combine like terms: 7-19 - 2a = -2 + 3a, and then -10 = 5a
2) solve this equation for a: a = -10/5 = -2.
The solution of 7-2a-5-14=-2+3a is a = -2.
F(x)= 650(1+.12)^x
f(x) = 650(1.12)^x
