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3 years ago

Quadrilateral ABCD has the following

Mathematics

1 answer:

Daniel [21]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

Because it’s a trapezoid and those can be trapezoid because they have one pair of parallel sides and a parallelogram has two pairs of parallel sides so a parallelogram is also a trapezoid.

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Which is not a common factor of 15, 45,and 90

Naddika [18.5K]

Answer:

6/90/45/30/18/9/2

Step-by-step explanation:

15: 3/5/15/1

45: 45/1/9/5/15/3/

90: 90/1/9/10/45/2/15/6/3/30/5/18

7 0

3 years ago

There are 8 cakes and we are dividing them into pieces. Each piece will be ⅕ of a cake. How many pieces will there be in all? Wr

natta225 [31]

Answer:

Step-by-step explanation:

8 piece of cakes times 5 pieces per cake = 40 pieces for the total cakes

7 0

3 years ago

Find all the solutions in there interval (0,2pi) for cos5x=-1/2

oee [108]

Answer:

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

$cos5x=-\frac{1}{2}$

Solving for 5x:

$5x=\frac{2\pi}{3}+2n\pi$

$5x=\frac{4\pi}{3}+2n\pi$

The values for x will be

$x=\frac{\frac{2\pi}{3}+2n\pi}{5}$

$x=\frac{\frac{4\pi}{3}+2n\pi}{5}$

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval $(0,2\pi)$

For n=0

$x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}$

$x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}$

For n=1

$x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}$

$x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}$

For n=2

$x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}$

$x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}$

For n=3

$x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}$

$x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}$

For n=4

$x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}$

$x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}$

For n=5 we would find values such as

$x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}$

$x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}$

which don't lie in the interval $(0,2\pi)$

The whole set of results is

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

6 0

4 years ago

Use the Pythagorean Theorem to solve the given problem. Hint: Draw a picture or diagram.

zimovet [89]

Here is the answer...hope this helps:)

7 0

2 years ago

If Angela has $500 to invest at 2.5% per annum compounded quarterly, how long will it be

11Alexandr11 [23.1K]

N = number of compounding periods
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1.00625) 
 Years = 0.17609125906 / 4 * 0.0027058933759
Years = 0.17609125906 / 0.0108235735 
Years = 16.2692348382 

Source Calculator
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5 0

3 years ago