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3 years ago

What happens to the total mass of the atoms involved in a chemical reaction

1 answer:

7 0

There won't be any change in the total mass of the atoms involved in a chemical reaction. According to the law of conservation of mass; it states that mass can neither be created nor destroyed in a chemical reaction. So, when atoms participate in a chemical reaction they might displace with other reactants but the total mass will remain the same.

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RainbowSalt2222 ☔

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A regular heptagon has an apothem of approximately 6.7 cm and a perimeter of approximately 45.5 cm.

Maurinko [17]

Answer:

304.85 cm²

Step-by-step explanation:

The area (A) of a polygon is calculated as

A = pa ( p is the perimeter and a the apothem ) , thus

A = 45.5 × 6.7 = 304.85 cm²

8 0

3 years ago

Which of the following are alternate interior angles

ehidna [41]

Answer:

2 and 8, 3 and 5

Step-by-step explanation:

uh no explanation needed

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3 years ago

The temperature in Denver had a high of 57℉ on Saturday. The temperature hit a record decrease within a 24 hour period, dropping

Likurg_2 [28]

Answer:

Step-by-step explanation:

Saturday: 57 Farenheit

Sunday: 12 Farenheit

Monday: -10 Farenheit

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3 years ago

What's the answer to the picture below

romanna [79]

9514 1404 393

Answer:

B. √900

Step-by-step explanation:

The solutions to the equation are ...

x = ±√900 = ±3√100 = ±10√9 = ±30

Of the offered choices, the only one that matches any of these is ...

√900

6 0

3 years ago

A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand

Tpy6a [65]

Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

We have to test the claim that the population mean is 10.5.

Let, NULL HYPOTHESIS, $H_0$ : $\mu$ = 10.5 {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, $H_a$ : $\mu \neq$ 10.5 {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 11

s = sample standard deviation = 2

$\mu$ = population mean

n = sample of values = 16

So, test statistics = $\frac{11-10.5}{\frac{2}{\sqrt{16} } }$ ~ $t_1_5$

= 1

Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the population mean is different from 10.5.

6 0

4 years ago