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nata0808 [166]
2 years ago
7

Identify what Number property is shown for each statement

Mathematics
2 answers:
Lunna [17]2 years ago
5 0

Answer:

Step-by-step explanation:

G. 10x3=3x10     1. Commutative property of multiplication

3. Associative property of Addition

F. (5x3)x4=5x(3x4)     4.Associative property of multiplication

J. If 11 = y then y = 11      5. Symmetric property

A. 21=21       6. Reflexive property

7. Transitive property

8. Zero property of multiplication

9. multiplicative inverse

D. 9x0=0    10. Zero property of multiplication

E. 4+0=4     11. Additive identity

H. 19x1=19   12. Multiplicative identity

B. If k=15 and 5 = 3m. Then k = 3m    This statement is not true.

This may be the transitive property, but this was written incorrectly. You have 15 in k = 15, but 5 in 5 = 3m.

C. 7+4=4+7      This is commutative property of addition, which is not listed above

I. 8x1/2=1     This statement is false. Maybe you meant 8 x 1/8 = 1. Then it is 9. Multiplicative inverse.

K. (6+2) + 1 = 6 + 2 + 1 This does not illustrate anything.

Maybe you missed the parentheses on the right side: 6 + (2 + 1). Then it is the associative property of addition.

L. 2+(2-)=0 If this were 2 + (-2) = 0, then it would be Additive Inverse, but I don't see this listed above.

Evgen [1.6K]2 years ago
3 0

1. Commutative property of multiplication = G. 10x3=3x10

3. Associative property of Addition = K. (6+2) + 1 = 6 + (2 + 1)

4. Associative property of multiplication = F. (5x3)x4=5x(3x4)

5. Symmetric property = J. If 11 = y then y = 11

6. Reflexive property = A. 21=21

7. Transitive property = B. If k=15 and 5 = 3m. Then k = 3m

8. Zero property of multiplication = D. 9x0=0

9. multiplicative inverse = I. 8x1/2=1

10. Zero property of multiplication = L. 2+(2-)=0

11. Additive identity = E. 4+0=4

12. Multiplicative identity = H. 19x1=19

Hope this helps!

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0.81859

Step-by-step explanation:

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When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select and test 56 b
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Answer:

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Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

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<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>

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\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}

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