The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as
Parabloid, x = 4y^2 + 4z^2
plane x = 4
x = 4y^2 + 4z^2
x = 4
4 = 4y^2 + 4z^2
4 = 4 (y^2 + z^2 )
1 = y^2 + z^2
from polar coordinates
y = r cos θ
z = r sin θ
r^2 = y^2 + z^2
<h3>limts of the integral</h3>
0 ≤ θ ≤ 2π
4r^2 ≤ x ≤ 4
0 ≤ r ≤ 1
where
a = 4
b = 4r^2
c = 2r
d = 0
The first integral using limits c and d gives:
The second integral using limits a and b
The third integral using limits 1 and 0 gives:
Read more on Triple integral here: brainly.com/question/27171802
Its 50/50; It’s a 1/2 chance it’ll land heads up and 1/2 it’ll and heads down
Answer:
14+5
= 19
that's my answer please have a great day
Step-by-step explanation:
What's A?
√(-80) = √(4²×5(-1)) = 4√5 √(-1) = 4√5i.