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2 years ago

It’s for pre college

Mathematics

2 answers:

Effectus [21]2 years ago

7 0

If you need an explanation to the other response:

A function does not have two different y values for one x value. According to the given points we see that at x=-1 y has two values (6 and -8). Therefore, it is not a function.

alexdok [17]2 years ago

3 0

Answer:

Not a function

Step-by-step explanation:

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Rewrite in simplest radical form 1/x^-3/6.

Aneli [31]

$\cfrac{1}{x^{- \frac{3}{6} }} = \cfrac{1}{x^{- \frac{1}{2} }} =x^{ \frac{1}{2} }= \sqrt{x}$

6 0

3 years ago

Is (1, 2) solution for this system of inequalities ?

diamong [38]

Answer:

MAYBE

Step-by-step explanation:

7 0

3 years ago

What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?

Harman [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \: 14.25 \: \% \: }}}}}$

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

Finding the Interest

The sum of principal and interest is called an amount.

From the definition,

$\boxed{ \sf{Amount = \: Principal + Interest}}$

plug the values

⇒ $\sf{14550 = 6000 + Interest}$

Swap the sides of the equation

⇒ $\sf{6000 + Interest = 14550}$

Move 6000 to right hand side and change its sign

⇒ $\sf{Interest = 14550 - 6000}$

Subtract 6000 from 14550

⇒ $\sf{Interest = \: 8550 \: }$

Interest = $ 8550

Finding the rate 

${ \boxed{ \sf{Rate = \frac{Interest \times 100}{Principal \times Time}}}}$

plug the values

⇒ $\sf{ Rate = \frac{8550 \times 100}{6000 \times 10} }$

Calculate

⇒ $\sf{Rate = \frac{855000}{60000} }$

⇒ $\sf{Rate = 14.25 \: \% \: }$

Hope I helped!

Best regards!!

8 0

3 years ago

A motorcycle is traveling at a constant speed of 75miles per hour. How many feet does it travel in 7seconds? Remember that 1 mil

Stella [2.4K]

770 feets per 7 seconds

5 0

3 years ago

Please help first real answer will get brainliest

KATRIN_1 [288]

Answer:

Step-by-step explanation:

a1(n-1) + D

d = 6

8 0

3 years ago