What number has 62 hundreds and 5 tens
2 answers:
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(4x^2-25)/(2x-5)=14
we hates fractions so m ultiply both sides by (2x-5)
4x^2-25=14(2x-5)
4x^2-25=28x-70
add 70 to both sides
4x^2+45=28x
subtract 28x fromoth sides
4x^2-28x+45=0
use quadratic formula which is
if you have
ax^2+bx+c=0 then
x=
a=4
b=-28
c=45
subsitute
x=
x=
x=
x=
or 
if we were to put 5/2 for x, the deonomentor would be equal to zero, so it cannot be used
answer is
x=9/2
we hates fractions so m ultiply both sides by (2x-5)
4x^2-25=14(2x-5)
4x^2-25=28x-70
add 70 to both sides
4x^2+45=28x
subtract 28x fromoth sides
4x^2-28x+45=0
use quadratic formula which is
if you have
ax^2+bx+c=0 then
x=
a=4
b=-28
c=45
subsitute
x=
x=
x=
x=
if we were to put 5/2 for x, the deonomentor would be equal to zero, so it cannot be used
answer is
x=9/2