Answer:
Explanation:
Velocity of plane relative to ground V_pg = ?
Given the velocity in vector form ,
velocity of plane relative to air V_pw = 120 cos30 i + 120sin30j
V_wg = 60 i
V_pg = V_pw +V_wg
= 120 cos30 i + 120sin30j + 60i
= 164 i + 60 j
magnitude
=251 km / h
=
Answer:
421.83 m.
Explanation:
The following data were obtained from the question:
Height (h) = 396.9 m
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
First, we shall determine the time taken for the ball to get to the ground.
This can be calculated by doing the following:
t = √(2h/g)
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 396.9 m
Time (t) =.?
t = √(2h/g)
t = √(2 x 396.9 / 9.8)
t = √81
t = 9 secs.
Therefore, it took 9 secs fir the ball to get to the ground.
Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:
Time (t) = 9 secs.
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
s = ut
s = 46.87 x 9
s = 421.83 m
Therefore, the horizontal distance travelled by the ball is 421.83 m
Answer:
Equilibrium quantity = 5
Equilibrium price = 40
Explanation:
given:
p = -x²-3x+80
p = 7x+5
For the equilibrium quantity the price from both the functions will be equal
thus, we have
-x² - 3x + 80 = 7x+5
⇒ x² +3x + 7x + 5 - 80 = 0
⇒x² + 10x - 75 = 0
now solving for x
x²- 5x + 15x -75 = 0
x(x-5) + 15(x-5) = 0
therefore, the two roots of the equation are
x = 5 and x = -15
since the quantity cannot be in negative
therefore, the equilibrium quantity will be = 5
now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation
thus,
p = -(5)² -3(5) + 80 = 40
or
p = 7(5) + 5 = 40
