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KIM [24]
3 years ago
6

A metal ball of specific heat capacity 400 joule per kgper celsius is allowed to fall from a height of 100 metre .If the ball on

hitting the ground stops and all the energy possessed by it is converted into heat energy calculate the rise in temperature of the Ball (g = 200 metre per second square)
Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0
First we'll calculate the energy it posesses

G.P.E = mgh = 0.2 * 10 * 100 = 200 J

Now we'll calculate the temperature rise

Q = m * c * (t2 - t1)
Q/(m * c) = t2-t1
t2 = Q/(m * c) + t1 = 200/(0.2 * 400) + 0 = <span>2.5 C</span>
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If two bodies have the same kinetic energy do they have the same momentum or not and why?
Mnenie [13.5K]
They do because if one thing is moving and the is there both moveing in once
6 0
3 years ago
A rope pulls a 20 kg box up. If the tension in the rope is 275 N, what is the acceleration of the box?
Nana76 [90]

Answer:

<h3>The answer is 13.75 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{275}{20}  =  \frac{55}{4}  \\

We have the final answer as

<h3>13.75 m/s²</h3>

Hope this helps you

4 0
3 years ago
What do generators do
777dan777 [17]

Answer:

generate electricity or power

3 0
4 years ago
Read 2 more answers
A 12.0 kg object is attached to a cord that is wrapped around a wheel of radius 10.0 cm. the acceleration of the object down the
olganol [36]

 a) We use the formula:

T = [g sinθ – a] * m

where g is gravity, θ is the angle, a is acceleration, m is mass

T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>

b) We use the formula for moment of interia:</span>

I = T * r² / a

I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>

c) The formula we can use here is:</span>

w = α * t = (a/r) * t

w = (2/.10) * 2

<span>w = 40 rad/sec</span>

6 0
3 years ago
The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration, skidding to a comp
Ber [7]

Answer: -6.80\ ms^{-2}

Explanation:

We know that the formula for acceleration is given by:

a=\dfrac{v-u}{t} , where v = Final velocity

u= Initial velocity

Given :  The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.

i.e. u=   110 km/h =\dfrac{110\times1000}{3600}\approx35.6\ m/s  [∵  1 km= 100 meters and 1 hour = 3600 seconds]

v=  0  m/s ( At brake , final velocity becomes 0)

t=4.5 seconds  

Substitute all the values in the formula , we get

a=\dfrac{0-30.56}{4.5}\approx-6.80\ ms^{-2}

Hence, the average acceleration of the car during braking is -6.80\ ms^{-2}.

5 0
3 years ago
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