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Anni [7]
2 years ago
14

Plz! How to solve this question? The answer is B.

Physics
1 answer:
LekaFEV [45]2 years ago
4 0

dhvjmdsgyddsfjdbfydgbgdfvdfshfgsdbfhdf nfdfh htiu4ewr huirhfhwref

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The speed of light in a solid is 1.24 x 108 m/s. <br> Calculate the index of refraction
Dahasolnce [82]

Answer:

125

Explanation:

7 0
2 years ago
A parallel-plate capacitor with plates of area 600 cm^2 is charged to a potential difference V and is then disconnected from the
Julli [10]

Answer:

<h2>a) Q = 0.759µC</h2><h2>b) E = 39.5µJ</h2>

Explanation:

a) The charge Q on the positive charge capacitor can be gotten using the formula Q = CV

C = capacitance of the capacitor (in Farads )

V = voltage (in volts) = 100V

C = ∈A/d

∈ = permittivity of free space = 8.85 × 10^-12 F/m

A = cross sectional area = 600 cm²

d= distance between the plates = 0.7cm

C = 8.85 × 10^-12 * 600/0.7

C = 7.59*10^-9Farads

Q = 7.59*10^-9 * 100

Q = 7.59*10^-7Coulombs

Q = 0.759*10^-6C

Q = 0.759µC

b) Energy stored in a capacitor is expressed as E = 1/2CV²

E = 1/2 * 7.59*10^-9 * 100²

E = 0.0000395Joules

E = 39.5*10^-6Joules

E = 39.5µJ

7 0
2 years ago
1. Earth releases about 44-46 Tw of heat, in fact heat can be converted into
Aleksandr [31]

Answer:

  even if it all could be used, it wouldn't be enough

Explanation:

The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.

Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if <em>all</em> of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.

8 0
3 years ago
An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers (n = 3.50
sasho [114]

Answer:

d = 6.43 cm

Explanation:

Given:

- Speed resistance coefficient in silicon n = 3.50

- Memory takes processing time t_p = 0.50 ns

- Information is to be obtained within T = 2.0 ns

Find:

- What is the maximum distance the memory unit can be from the central processing unit?

Solution:

- The amount of time taken for information pulse to travel to memory unit:

                            t_m = T - t_p

                            t_m = 2.0 - 0.5 = 1.5 ns

- We will use a basic relationship for distance traveled with respect to speed of light and time:

                           d = V*t_m

- Where speed of light in silicon medium is given by:

                           V = c / n

- Hence,              d = c*t_m / n

-Evaluate:           d = 3*10^8*1.5*10^-9 / 3.50

                           d = 0.129 m 12.9 cm

- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm

8 0
3 years ago
An object has a mass of 8.00kg. What is the gravitational force on the object by the earth
Firdavs [7]
78.4 F because you do 8.00 muliplyed by 9.8
6 0
2 years ago
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