Plz! How to solve this question? The answer is B.

Suppose that you take a 10 kg mass on the surface of the earth and then place it on the moon. What will

sergey [27]

Answer:

10 kg

Explanation:

The mass of an object does not change even if the amount of gravtiy changes.

5 0

3 years ago

Filling in the blanks

Goshia [24]

A) turning
b)greater
c) greater
d) force*distance
e)Nm

3 0

3 years ago

¿Qué pueden decirnos las capas de hielo del Ártico sobre nuestros cambios atmosféricos?

NARA [144]

Ya me voy por que es nut consada busotros

7 0

3 years ago

The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these

harina [27]

Answer:

Electric field magnitude

E = K/qd

Where

K = kinetic energy of electron

d = electron distance

q = charge

Explanation:

Given the relationship between workdone and energy

Work-energy theorem:

Net workdone = Energy change

W = ∆E

In this case

W = ∆K.E

And,

∆K.E = K(final) - K(initial)

To stop the kinetic energy | K(final) = 0

K(initial) = K (given)

∆K.E = 0 - K = -K

Let the electric force on the electron has magnitude F.

And

W = -Fd = ∆K.E = -K

-Fd = -K

F = K/d .....1

The magnitude of the electric field E that can stop these electron in a distance d:

E = F/q ......2

Where q is the charge on electron.

substituting equation 1 to 2

E = (K/d)/q = K/qd

E = K/qd

3 0

4 years ago

A solid sphere of radius R is made of a metallic conductor. A hollow spherical shell of the same radius R is made of the same co

Harrizon [31]

1-2) They have same surface charge density

3-4) The metallic conductor has greatest surface charge density

Explanation:

1-2)

In a conductor, the charge carriers (mainly electrons) are free to move. Therefore, as a result, they tend to move at the largest possible distance from each other, because of the repulsive force that they exert on each other.

The configuration that maximize the distance between the charge carriers for a solid sphere of metallic conductor is the one in which all the electrons are on the surface, and they are equally spaced between each other. This means that for the solid sphere of radius R, the excess charge Q will be entirely spread over the surface of the sphere.

Similarly, the excess charge Q on the hollow spherical shell (which is also made of the same conducting material) will also be spread over the surface with the charge carriers at the maximum distance from each other. Therefore, the surface charge density for both objects will be

$\sigma = \frac{Q}{4\pi R^2}$

where R is the radius of the two spheres.

3-4)

In this case, the surface charge density on the two objects is different.

In fact, on the metallic sphere (conducting) the surface charge density is (as explained in part 1):

$\sigma = \frac{Q}{4\pi R^2}$

Hoever, the second sphere is made of an insulating material. In an insulator, the charge carriers are not free to move. If the initial charge Q is spread across the all sphere (which is not hollow), this means that some of the charge will actually also be inside the sphere. So the charge deposited on the surface, Q', will be less than the total charge Q. Therefore, the surface charge density will be

$\sigma' = \frac{Q'}{4\pi R^2}$

And since Q' < Q, this means that $\sigma'$ , so the conducting sphere has a greatest surface charge density.

4 0

3 years ago