Answer:
The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C
Explanation:
The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m), will be evaluated as follows:
Since x > 0
![E_{x} = 2\pi \sigma k [1-\frac{x}{\sqrt{x^2 +R^2}}]](https://tex.z-dn.net/?f=E_%7Bx%7D%20%3D%202%5Cpi%20%5Csigma%20k%20%5B1-%5Cfrac%7Bx%7D%7B%5Csqrt%7Bx%5E2%20%2BR%5E2%7D%7D%5D)
σ is surface charge density = 5.88 × 10⁻⁶ C / m²
R is the radius = 7.52cm = 0.0752m
position x = 1.01m
k is coulomb force constant = 8.99 × 10⁹ Nm² / C²
![E_{x} = 2\pi ( 5.88X10^{-6})(8.99 X10^9)[1-\frac{1.01}{\sqrt{1.01^2 +0.0752^2}}]](https://tex.z-dn.net/?f=E_%7Bx%7D%20%3D%202%5Cpi%20%28%205.88X10%5E%7B-6%7D%29%288.99%20X10%5E9%29%5B1-%5Cfrac%7B1.01%7D%7B%5Csqrt%7B1.01%5E2%20%2B0.0752%5E2%7D%7D%5D)
= 996.54 N/C
Therefore, The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C
(a) The velocity of the first ball before the collision with the second ball is 11.18 m/s.
(b) The final velocity of the two balls after the collision is determined as 5.59 m/s.
<h3>
Speed of the block when pushed by the spring</h3>
The speed of the block when pushed by the spring is calculated as follows;
K.E = Ux
¹/₂mv² = ¹/₂kx²
mv² = kx²
v² = kx²/m
v² = (25 x 0.5²)/0.05
v² = 125
v = 11.18 m/s
<h3>Final velocity of the two balls after the collision</h3>
The velocity of the two balls after the collision is calculated as follows;
Pi = Pf
where;
- Pi is initial momentum
- Pf is final momentum
m1u1 + m2u2 = v(m1 + m2)
0.05(11.18) + 0.05(0) = v(0.05 + 0.05)
0.559 = 0.1v
v = 5.59 m/s
Learn more about velocity here: brainly.com/question/4931057
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Answer:
Horse/Speed
55 mph
rounded to the tenth? either 60 or 50
but 350 would stay like that i believe!
Explanation:
Answer:
Vs/c = 20 [m/s]
Explanation:
This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.
We are asked for the velocity of the sailboat with respect to an observer located in the canoe.
![V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s]](https://tex.z-dn.net/?f=V_%7Bs%2Fc%7D%3DV_%7Bsailboat%7D-V_%7Bcanoe%7D%5C%5CV_%7Bs%2Fc%7D%3D15-%28-5%29%5C%5CV_%7Bs%2Fc%7D%3D20%5Bm%2Fs%5D)
Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.
The release of free energy drives the spontaneous reaction.
Spontaneity can be <span>determined
using the change in </span>Gibbs free energy
(the thermodynamic potencial):
delta G=delta H – T*delta
S
where delta H is the enthalpy and delta S is the entropy.
The direction (the sign) of delta G depends of the changes
of enthalpy and entropy. If delta G is negative then the process is
spontaneous.
In our case, both delta H and delta S are negative values, the
process as said is spontaneous which means that it may proceed in the forward
direction.
