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3 years ago

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A 12.0 kg object is attached to a cord that is wrapped around a wheel of radius 10.0 cm. the acceleration of the object down the

frictionless incline is measured to be 2.00 m/s2. assuming the axis of the wheel to be frictionless, determine
a.the tension in the rope,
b.the moment of inertia of the wheel, and
c.the angular speed of the wheel 2.00 s after it begins rotating, starting from rest.

1 answer:

olganol [36]3 years ago

6 0

a) We use the formula:

T = [g sinθ – a] * m

where g is gravity, θ is the angle, a is acceleration, m is mass

T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>

b) We use the formula for moment of interia:</span>

I = T * r² / a

I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>

c) The formula we can use here is:</span>

w = α * t = (a/r) * t

w = (2/.10) * 2

<span>w = 40 rad/sec</span>

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