Answer:
y=-3 x=4
Step-by-step explanation:
y=3x+3
y=3x+3 y=x-1
+<u>1</u><u> </u><u> </u><u> </u><u> </u><u>+</u><u>1</u>
y+1=x
y=3(y+1)+3
y=3y+3+3
y=3y+6
<u>-3y=-</u><u>3y</u>
-2y=6
-y=3
<u>y=</u><u>-</u><u>3</u>
3=x-1
<u>+1=+1</u>
<u>4</u><u>=</u><u>x</u>
Answer:
The coordinates of D are (8,3)
Step-by-step explanation:
We have quadrilateral ABCD being a parallelogram with coordinates A(3,2), B(5,4), C(10,5), and D(a,b).
We want to find the coordinates of D.
Since ABCD is a parallelogram, the diagonals AC and BD bisects each other.
The midpoint of AC is (13/2,7/2).
This is also the midpoint of BD.
By the midpoint rule:

This implies that:

Similarly,

The coordinates of D are (8,3)
Answer:
option B
3
Step-by-step explanation:
Given in the question an expression

Whole numbers are positive numbers, including zero, without any decimal or fractional parts.
Possible range of domain will be 1 ≤ x ≤ 48
We know that perfect square between 1 and 48 are
1 , 4 , 16 , 25 , 36
1)
x = 3
√48/3 = √16 = 4
2)
x = 12
√48/12 = √4 = 2
3)
x = 48
√48/48 = √1 = 1
Answer:
5
Step-by-step explanation:
ok thanks