All categories

2 years ago

A car used 5 2/3 gallons of fuel on a 3 hour trip. How many gallons were used each hour?

Mathematics

1 answer:

mr_godi [17]2 years ago

5 0

Answer:

2. 1 8/9 gallons

Step-by-step explanation:

5 2/3 divided by 3

5.66666667/3 = 1.88888889

.88888889 = 8/9

1 + 8/9 = 1 8/9

You might be interested in

I NEED HELPPPPP QUICK PLEASE HELP THANKS

stepladder [879]

Answer:

18000$

Step-by-step explanation:

Frim the text you have the formula:

V=c-crt

where,

c=30000

r=0.1

t=4

So, new value after 4y:

V=30000-4*0,1*30000=30000-12000=18000

6 0

2 years ago

Is this a true statement? 0.3711 > 0.3801

disa [49]

NO. It's FALSE.

$0.\ 3\ 7\ 1\ 1\\||\ ||\wedge\\0.\ 3\ 8$

therefore 0.3801 > 0.3711

4 0

2 years ago

Find the value of x and then classify the triangles

ZanzabumX [31]

6. x = 16; it's a scalene triangle

7. x = 45; it's a right triangle.

8 0

2 years ago

The ratio of the mass of an ant to the mass it can carry 1:50

slavikrds [6]

The ratio 1:50 means that an ant can carry an object heavy 50 times its mass.

So, if the mass of the ant is 0.4 grams, it can carry at most 50 times that mass, i.e. 50x0.4 = 20 grams

In order to answer the second question, you need to consider your mass and multiply it by 50: if you were as strong as an ant, you could lift that weight!

6 0

3 years ago

Pat needs to determine the height of a tree before cutting it down to be sure that it will not fall on a nearby fence. The angle

dem82 [27]

Answer:

229.23 feet.

Step-by-step explanation:

The pictorial representation of the problem is attached herewith.

Our goal is to determine the height, h of the tree in the right triangle given.

In Triangle BOH

$Tan 60^0=\dfrac{h}{x}\\h=xTan 60^0$

Similarly, In Triangle BOL

$Tan 50^0=\dfrac{h}{x+60}\\h=(x+60)Tan 50^0$

Equating the Value of h

$xTan 60^0=(x+60)Tan 50^0\\xTan 60^0=xTan 50^0+60Tan 50^0\\xTan 60^0-xTan 50^0=60Tan 50^0\\x(Tan 60^0-Tan 50^0)=60Tan 50^0\\x=\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0} ft$

Since we have found the value of x, we can now determine the height, h of the tree.

$h=\left(\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0}\right)\cdotTan 60^0\\h=229.23 feet$

The height of the tree is 229.23 feet.

5 0

3 years ago