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Veseljchak [2.6K]
3 years ago
8

Can anyone fix this code for me?

Computers and Technology
1 answer:
nignag [31]3 years ago
3 0

Answer:

function start(){

move();

for(var i = 0; i < 2; i++){

move();

move();

jumpHurdle();

if(frontIsClear()){

move();

}

}

move();

move();

move();

function jumpHurdle(){

turnLeft();

move();

turnRight();

move();

turnRight();

move();

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A sequence of repetitive operations performed to evaluate the ability of a PC to operate at peak efficiency for a defined time p
iragen [17]

Answer:

False.

Explanation:

The description provided matches better with Software performance testing, and shouldn't be confused with a benchmark.

In computing, a benchmark is a tool or software designed to measure the average performance of another program, by running several tests and trials against it.

A performance testing is designed to measure the performance and responsiveness of a computer system (not a program) under a heavy workload.

8 0
3 years ago
What is the minimum amount of hard drive space required for a 64-bit Windows 10 installation?
BaLLatris [955]

The minimum requirements for a 64-bit Windows 10 installation are 2 GB of RAM and a minimum of 16 GB of space on the hard drive.

<em>Hope this helps :)</em>

7 0
1 year ago
four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,
marshall27 [118]

Answer:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2

Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

  • 1s² 2s² 2p⁶ 3s² 3p⁶   : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

  • n = 3

  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
  • (3, 1, -1, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
5 0
3 years ago
Which tab of the ribbon includes the links group for creating hyperlinks or internal references?
Deffense [45]
The correct answer is D.File
5 0
3 years ago
Read 2 more answers
Program 4 - Pick color Class Create a class that randomly pick a color from an array of colors: string colors[7]; Have the color
xxMikexx [17]

Answer:

#include<cstdlib>

#include<bits/stdc++.h>

#include<time.h>

using namespace std;

class Colors{

string colors[7];

public:

void setElement(int,string);

void printAllColors();

void printRandomColor();

};

void Colors::setElement(int index,string color){

colors[index] = color;

}

void Colors::printAllColors(){

cout << "Printing all the colors:\n";

for(int i=0;i<7;i++){

cout << colors[i] <<"\t";

}

}

void Colors::printRandomColor(){

srand (time(NULL));

int index = rand() % 7;

cout<< "\n\nThe random picked color:";

cout << colors[index] << endl;

}

int main(){

Colors color;

color.setElement(0,"red");

color.setElement(1,"orange");

color.setElement(2,"yellow");

color.setElement(3,"green");

color.setElement(4,"blue");

color.setElement(5,"indigo");

color.setElement(6,"violet");

color.printAllColors();

color.printRandomColor();

}

to get the random color we are using srand and rand function. we are using time as seed to srand() function,because every time the time is changed. And based on that we are using rand() function and doing mod with 7 with the random number to get the index between 0 to 6, as ut array size is 7(0 to 6).

In the setElement(int index,string color) method we are inserting the value of colors in the colors array based on index.

In the printAllColors() function we are printing all the colors in the array.

In the printRandomColor() er are printing any random color based on rand() function.

and in main() we are initializing the string array with colors and calling the functions.

7 0
3 years ago
Read 2 more answers
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