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Shalnov [3]
3 years ago
14

What is the purpose of a div?

Computers and Technology
1 answer:
taurus [48]3 years ago
5 0

Answer:

I'd choose A, all of the above.

Reasoning Why:

I'll be taking you on a step to step process on why I inputted the answer.

The <div>, is basically like a container that you can group tougher, why this is great is because you can edit the div using a background-color effecting that group such as the following..

EXAMPLE OF BACKGROUND-COLOR DIV (background-color)

<!DOCTYPE html>

<html>

<head>

<title>Brainly Example | HTML Div</title>

<style>

#byexample{

background-color:red;

/*Example of the Background-color attrib*/

/*You can also use the background-image attrib, however I recommend you checkout W3Schools, on that topic.*/

}

</style>

</head>

<body>

<div id="byexample">

<p>Just some random text to demonstrate.</p>

</div>

</body>

</html>

END OF EXAMPLE

You can also, in the <div> change multiple styles of an element in the div. However, if do want to change the styles of a single element you would need to nest it.

<!DOCTYPE html>

<html>

<head>

<title>Brainly Example | HTML Div</title>

<style>

#byexample #text{

background-color:red;

color:yellow;

}

</style>

</head>

<body>

<div id="byexample">

<p id="text">Just some random text to demonstrate.</p>

</div>

</body>

END OF EXAMPLE

Lastly, you can group elements using divs, as stated in openclassroom (website).

Anyways, I hope this helped!

Happy coding!

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Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument
timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0
3 years ago
A=4x^2.(x-2y)-20x.(2y-x)
Luda [366]

Answer:

please give point

6 0
2 years ago
The IntList class contains code for an integer list class. Study it; notice that the only things you can do are: create a list o
torisob [31]

Explanation:

public class Int_List

{

protected int[] list;

protected int numEle = 0;

 

public Int_List( int size )

{

list = new int[size];

public void add( int value )

{

if ( numEle == list.length )

{

System.out.println( "List is full" );

}

else

{

list[numEle] = value;

numEle++;

}

}

public String toString()

{

String returnStr = "";

for ( int x = 0; x < numEle; x++ )

{

returnStr += x + ": " + list[x] + "\n";

}

return returnStr;

}

}

public class Run_List_Test

{

public static void main( String[] args )

{

 

Int_List myList = new Int_List( 7 );

myList.add( 102 );

myList.add( 51 );

myList.add( 202 );

myList.add( 27 );

System.out.println( myList );

}

}

Note: Use appropriate keyword when you override "tostring" method

8 0
3 years ago
How does this happen on brainly????
Trava [24]

what do you mean????

4 0
3 years ago
Read 2 more answers
Jorge is sending a large image file to a friend as part of a shared classroom project. Which of the following is most likely tru
madreJ [45]

Answer:

D. The image will require fewer bits in order to be represented.

Explanation:

Lossy compression algorithms are typically better than lossless compression algorithms at reducing the number of bits needed to represent a piece of data.

5 0
3 years ago
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