Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Rate/ speed = distance / time;
= 1/2mile / 300 seconds;
= 0.001666666..... mile/second
Answer:
x= 11
Step-by-step explanation:
The slope is 0 because there is no slope it is not pointing up nor is it down. It is just a straight line. I hope this helps!! Have a nice day!!
Yeah that is correct. 3/4 is equal to .75