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igor_vitrenko [27]
3 years ago
12

If you can do something fast and with strength, you have balance. O A True O B. False ​

Physics
1 answer:
Gnesinka [82]3 years ago
8 0

Answer:

FALSE

Explanation:

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The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota
german

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

  • An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
  • Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
  • Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc.
  • Most electromagnetic waves are transverse in nature.
4 0
3 years ago
The revolution of the earth around the sun demonstrate what motion?​
olga2289 [7]

Answer:

Anticlockwise directions

Please mark me Brainliest to help me

3 0
2 years ago
How would you change the distance between two charged particles to increase the electric force between them by a factor of 16
Naily [24]

The electrostatic force between two charges is inversely
proportional to the square of the distance between them.

So if you want to multiply the force by, say, ' Q ',
you need to multiply the distance by  ( 1 / √Q ) .

We want to multiply the force by 16, so we need to
multiply the distance by    ( 1 / √16 )  =  ( 1 / 4 ) .

The distance should be changed to  1/4  of what it is now.

4 0
4 years ago
Read 2 more answers
Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
4 years ago
Guyz... Its my first question in this app... Pls do answer​
Basile [38]

Answer:

1.414

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1.  So:

1 sin 45° = n sin 30°

n = sin 45° / sin 30°

n = 1.414

Round as needed.

6 0
3 years ago
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