Answer:
Velocity of Object with 2 kg= 3.390 m/s
Velocity of Object with 3 kg= 3.404 m/s
Explanation:
From the picture, it can be seen that object B is initially at rest while object A is travelling at a speed of 5m/s. After the collision, Object A moves at an angle of 65 degrees while object B moves at an angle of 37 degrees.
We also know that momentum of a closed system is conserved.
Initial momentum along the x-axis = 2*5.5 = 11
Initial momentum along y-axis = 0
Final momentum along x-axis= a*Cos(65)*2 +b*Cos(37) *3= 11 (a is the velocity of object A of 2 kg after collision where as b is the velocity of object B of 3 kg after collision. velocity is multiplied by cosines of the angle from x axis to give the horizontal component of the velocities).
Final momentum along y-axis = a*Sin(65)*2 - b*Sin(37)*3 =0 (We can see that vertical components of velocity are opposite in direction to each other)
Solve both the equations simultaneously for a and b.
Acceleration because it is at a rise in speed. The formula for acceleration is Speed/Time.
Answer:
C. The number of protons.
Explanation:
All atoms of mercury will remain the same while different isotopes may have different number of neutrons.
For example, mercury has 80 protons, correlating with its atomic number. However, the number of protons, neutrons, and electrons could vary between each atom. If there are 80 protons, then there has to be 80 electrons. This means that the protons have to be the same in order to apply to all atoms of mercury
It is biotic and nest are strong
Answer:
Explanation:
Drag force is given by
C = Drag coefficient is constant
A = Area is constant
= Velocity of the passenger jet = 1200 km/h = 
= Velocity of the prop plane = 
= Density of the air where the jet was flying = 
= Density of the air where the prop plane was flying = 
The ratio of the drag forces is .
