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sattari [20]
3 years ago
6

The speed limit on a highway is 65 miles per hour. a driver wants to travel 487 miles along the highway in the next 9.8 hours. w

hat is the longest span of rest time available to the driver to complete this journey without ever exceeding the speed limit?
Physics
1 answer:
topjm [15]3 years ago
7 0
1) 487 miles / 65 miles per hour  = 7.5h at max speed
2) 9.8h - 7.5h = 2.3h rest time avaliable 


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Acceleration due to gravity is
Korolek [52]

Acceleration due to gravity is different in every location, because gravity itself is different in every location.

Here are a few values of gravitational acceleration in various places:

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-- Surface of Mars . . . 3.7 m/s²

-- Surface of the Sun . . . 274 m/s²

-- Surface of Earth . . . 9.8 m/s²

-- In orbit 300 miles above the Earth's surface . . .  8.5 m/s²

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4 years ago
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3 0
4 years ago
A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material,
Ad libitum [116K]

This question is incomplete, the complete question is;

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

a) (In2)R

b) 4R

c) R/(In2)

d) 2R

e) R

Answer: Option e) R is the correct answer.

Explanation:

Given that;

Inner radius = a

Outer radius = b

Conical Cylinder

∫dR = ∫(edr/2πrL)

R = e/2πL In e |ᵇₐ

R = e/2πL In(b/a) ------------- let this be equation 1

Taking a look at the second cone

a' = 2a

b' = 2a

R' = e/2πL In(2b/2a)

{L = L'}

R' = e/2πL In(b/a) -------let this be equation 2

now lets compare the two equation

R = e/2πL In(b/a)

R' = e/2πL In(b/a)

so R' = R

Therefore Option e) R is the correct answer.

8 0
3 years ago
Which statement is true?
ser-zykov [4K]

D is definitely the correct choice here.

I think a case could also be made for choice-B, but that would be a tough, complex operation.

8 0
3 years ago
Una caja de 40.0 kg se desliza 4.00 m hacia arriba por un plano inclinado de 26° con respecto a la acción de una fuerza de 340 N
otez555 [7]

Answer:

W = 320.30 J

Explanation:

To calculate the net work done over the block you take into account all implied forces:

\Sigma F=F+F_gsin\theta-F_fcos\theta  (1)

The gravitational force and friction force are against the applied force F.

θ = 26°

F: applied force = 340N

Fg: gravitational force = Mg = (40.0kg)(9.8m/s^2) = 392N

Ff: friction force = \mu N=\mu Mg=(0.250)(392N)=98N

Next, you replace to obtain the net force:

F_N=(340N)-(392N)sin(26\°)-(98N)cos(26\°)\\\\F_N=80.07N

Finally, the net work, for 4 m, is:

W_N=F_Nd=(80.07N)(4m)=320.30J

6 0
3 years ago
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