Answer:
<h3>After 3seconds</h3>
Explanation:
A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Using the formula for calculating speed expressed as;
Speed = Distance/Time
Given;
Distance = 3km = 3000m
Speed = 1000m/s
Required
How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)
From the formula;
Time = Distance/speed
Time = 3000/1000
Time = 3seconds
Hence the sound of the aircraft is heard after 3 seconds
If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.
If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.
Answer:
idont no just follow me please sorry need point
Here's the solution :
Let's find the final velocity :
Initial velocity (u) = 0 (cuz it started from rest)
Final velocity (v) = 8 m/s
Time taken (t) = 10 sec
now, we know that :
Acceleration = 0.8 m/s²
<span>In a single cell organism, the
absorption of nutrients and control of certain things to <span>come inside or go outside the cell directly involves
the cell membrane. Although, the basic function of the cell membrane is to
protect the cell from its surroundings. It also facilitates the transport of
substances needed for survival.</span></span>
