The four powers have zero (0) in common
<h3>Indices </h3>
From the question, we are to determine what the four powers have in common
In the question, we can observe that the four powers have 0 in common.
The value of each of the expressions is 1.
Hence, the four powers have zero (0) in common.
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So for this problem you know that 15 is 1/4 of an hour so to get the amount of papers each individual could deliver by themselves in an hour you would multiply the amount they can deliver in 15 minutes by 4. Denny delivers 6 so multiplying that by 4 is 24. Next Brendan delivers 5 in 15 minutes so multiplying that by 4 you get 20. The final step is to add 20 and 24 to get the total amount of papers between the two of them that gets delivered in an hour. This will result in your answer of 44.
Answer:
5 + y ≥ 7
Step-by-step explanation:
"The sum of 5 and y"
The sum of two items will be the two items added, and in this case, it is 5 and y, or
5 + y.
"Greater than or equal to 7"
Here, use the symbol, ≥, and 7.
≥ 7
Combine those to get the final equation:
5 + y ≥ 7.
A is the answer because x^2-6x-7 is (x-7)(x+1).
Answer:
1,-3,-5
Step-by-step explanation:
Given:
f(x)=x^3+7x^2+7x-15
Finding all the possible rational zeros of f(x)
p= ±1,±3,±5,±15 (factors of coefficient of last term)
q=±1(factors of coefficient of leading term)
p/q=±1,±3,±5,±15
Now finding the rational zeros using rational root theorem
f(p/q)
f(1)=1+7+7-15
=0
f(-1)= -1 +7-7-15
= -16
f(3)=27+7(9)+21-15
=96
f(-3)= (-3)^3+7(-3)^2+7(-3)-15
= 0
f(5)=5^3+7(5)^2+7(5)-15
=320
f(-5)=(-5)^3+7(-5)^2+7(-5)-15
=0
f(15)=(15)^3+7(15)^2+7(15)-15
=5040
f(-15)=(-15)^3+7(-15)^2+7(-15)-15
=-1920
Hence the rational roots are 1,-3,-5 !
