Answer:
2.49 × 10⁶ molecules
Explanation:
Given data
- Pressure (P): 9.25 × 10⁻¹⁴ atm
- Volume (V):
We can calculate the moles of gas using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 9.25 × 10⁻¹⁴ atm × 1.10 × 10⁻³ L / (0.0821 atm.L/mol.K) × 300.0 K
n = 4.13 × 10⁻¹⁸ mol
1 mole contains 6.02 × 10²³ molecules (Avogadro's number). The number of molecules in 4.13 × 10⁻¹⁸ moles is:
4.13 × 10⁻¹⁸ mol × (6.02 × 10²³ molecule/1 mol) = 2.49 × 10⁶ molecule
If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability. Example of an unstable atom with a single electron in its outer-most shell. ... In covalent bonds, atoms share electrons to achieve stability.
Hope this helped!
Answer:
Homoanular dienes have a greater base value than heteroanular dienes
Explanation:
Woodward in 1945 gave a set of rules relating the wavelength of maximum absorption to the structure of a compound. These rules were modified by Fieser in 1959. These sets of rules describe the absorption of organic molecules in the UV region of the electromagnetic spectrum.
Each system of diene or triene has a given fixed value at which maximum absorption is expected to occur according to Woodward rules. This given fixed value is called the base or parent value. If the two double bonds are trans to each other, the diene is said to be transoid. If the two double bonds belong to different rings, the system is said to be heteroanular and the base value in each case is 215nm. If the double bonds are cis to each other (cisoid), or the two double bonds are in the same ring (homoanular), then the base value is 253nm.
Since λmax = base value + ∑ substituent contributions + ∑ other contributions, if the other contributions are not very significant, homoanular diene will have a greater λmax because of its larger base value compared to heteroanular diene. This correlates well with the fact that conjugated systems absorb at a longer wavelength.
Answer:
Empirical formula is KHO₃C.
Explanation:
Given data:
Percentage of potassium = 39.0%
Percentage of hydrogen = 1.01%
Percentage of carbon = 12.0%
Percentage of oxygen = 47.9%
Empirical formula = ?
Solution:
Number of gram atoms of K = 39.0/ 39 = 1
Number of gram atoms of H = 1.01 / 1.01 = 1
Number of gram atoms of O = 47.9 / 16 = 3
Number of gram atoms of C = 12 / 12 = 1
Atomic ratio:
K : H : O : C
1/1 : 1/1 : 3/1 ; 1/1
1 : 1 : 3 : 1
K : H : O :C = 1: 1 : 3 : 1
Empirical formula is KHO₃C.
