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TEA [102]
3 years ago
10

Consider 55 ml of water (h2o) in a beaker and 55 ml of acetone [(ch3)2co] in an identical beaker under identical conditions. com

plete the sentences to explain the relationship between the vapor pressure of water and acetone. match the words in the left column to the appropriate blanks in the sentences on the right. helpreset larger than at the same rate as more slowly than the same as weaker water will evaporate more quickly than acetone. the vapor pressure of acetone is smaller than than that of water at the same temperature. this is because the intermolecular forces between acetone molecules are stronger than those between water molecules.
Chemistry
1 answer:
fenix001 [56]3 years ago
4 0
The correct sentence is this:
THE VAPOUR PRESSURE OF ACETONE IS SMALLER THAT THAT OF WATER AT THE SAME TEMPERATURE.
Acetone will evaporate more quickly that water when exposed, this is because, its vapour pressure is smaller than that of water. The vapour pressure of water is greater, thus, at the same temperature and pressure, it will take less pressure to vapourize acetone.

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A 1.775g sample mixture of potassium hydrogen carbonate is decomposed by heating. if the mass loss is 0.275g what is the percent
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A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

  • Step 1: Write the balanced equation for the decomposition of KHCO₃.

2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)

The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.

  • Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.

In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.

0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃

  • Step 3: Calculate the mass percentage of KHCO₃ in the sample.

There are 1.25 g of KHCO₃ in the 1.775 g sample.

%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

Learn more about decomposition reactions here: brainly.com/question/14219426

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