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Margarita [4]
3 years ago
14

Periodic Table Escape Enter the correct 4 digit code (no spaces) *

Chemistry
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

What are you asking???

Explanation:

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Use the periodic table to identify the molar mass of each element below. Answer without doing any calculations.
Delicious77 [7]

Answer:

Beryllium (Be) : 9.01 g/mol

Silicon (Si) : 28.09 g/mol

Calcium (Ca) : 40.08 g/mol

Rhodium (Rh) : 102.91 g/mol

Explanation:

8 0
3 years ago
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In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water:
Marina CMI [18]

Explanation:

in the presence of excess oxygen methane burns to prduce carbon (iv) oxide and water ....this is called complete combustion...

6 0
3 years ago
Calculate the frequency in hertz of electromagnetic radiation that has a wavelength of 645.0 nm. (c = 3.00 X 10⁸ m/s)
bazaltina [42]

Answer:

1/wavelength

c=1/alpha

6 0
3 years ago
How many moles are in 75.0 grams of nitrogen gas, N2?
Westkost [7]

<u>Given:</u><u>                                                                                                                       </u>

Mass of Nitrogen (N₂) gas = 75 grams

<u>Finding the number of moles of N₂:</u><u>                                                                     </u>

We know that the molar mass of N₂ is 28 grams/mole

Number of moles = Given mass / Molar mass

Number of moles = 75 / 28

Number of moles = 2.68 moles

Hence, there are 2.68 moles in 75 grams of Nitrogen Gas

7 0
3 years ago
Based on the trend in the table, hypothesize what the volume of the sample at 400K would be.
mariarad [96]

Answer: The volume of sample at 400 K is 285cm^3

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T     (At constant pressure and number of moles)

{\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas  = 257cm^3

V_2 = final volume of gas  = ?

T_1 = initial temperature of gas  = 360 K

T_2 = final temperature of gas  = 400 K

Putting in the values we get:

{\frac{257}{360}=\frac{V_2}{400}

V_2=285cm^3

Thus volume of sample at 400 K is 285cm^3

6 0
3 years ago
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