The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
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Answer:
π
V-foam = 4r³( 2 - ----- )
3
Step-by-step explanation:
Let the radius of the sphere be r. Then the volume of the sphere is
V = (4/3)(π)(r³).
Next, recognize that the side length of the cube is 2r, and that the volume of the cube is thus
V = (2r)³, or 8r³.
Then the volume of the foam is equal to the volume of the cube less the volume of the sphere:
V-foam = 8r³ - (4/3)(π)(r³). This could be factored into
π
V-foam = 4r³( 2 - ----- )
3
I am not sure, but I think you are talking about the least square method
