Hello,
if the solution is infinite : the line x-3y=4 ,
so there is one line and not 2
==>x-3y=4 multiplied by 2
2x-6y=8=Q
Q=8
Answer:
j=49
Step-by-step explanation:
Answer:
10/11
Step-by-step explanation:
The fractions already have like denominators so you just add the numerators as there is no need to find the LCM but just in case
Hi there!
First, let's create an equation for the table: m = 2n + 40. Using this equation, we can find the values of x, y, and z.
WORK:
x = 2(4) + 40
x = 8 + 40
x = 48
y = 2(5) + 40
y = 10 + 40
y = 50
z = 2(6) + 40
z = 12 + 40
z = 52
Next, using the equation, we know that the initial investment would be 40, since that is the y-intercept of the equation. To express M in terms of N, that would be our equation m = 2n + 40. To find 10 years, we'll plug in 10 for n.
WORK:
m = 2(10) + 40
m = 20 + 40
m = 60 after 10 years
To figure out when his investment would double, we'll need to use 80 (double his initial investment of 40) in place of m.
WORK:
80 = 2n + 40
40 = 2n
n = 20 years
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
I strongly recommend that you find an illustration of an ellipse that features the three distances a, b and c. You could Google "ellipse" and sort through the various illustrations that result, until you find the "right one."
There is an equation that relates a, b and c for an ellipse. It is a^2 = b^2 + c^2.
a is relatively easy to find. It is the distance from the center (0,0) of your ellipse to the right-hand vertex (20,0). So a = 20.
b is the distance from the center (0,0) of your ellipse to the right-hand focus (16,0). So b = 16. You could stop here, as it was your job to find b.
Or you could continue and find a also. a^2 =b^2 + c^2, so
here a^2 = 16^2 + 20^2. Solve this for a.
