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ryzh [129]
2 years ago
12

Beryllium (Be) has four electrons. Fluorine (F) has nine electrons. Which chemical formula shows the correct subscripts for the

product of the reaction when beryllium and fluorine combine
Chemistry
2 answers:
LiRa [457]2 years ago
8 0

The correct chemical formula for the product of the reaction when beryllium and fluorine combine is BF₂.

The valence electron of an atom determines how an atom goes into bonding.

Beryllium(Be) has 4 electron and has 2 valence electron. To fulfil the octet rule, it can easily give out this 2 electron during bonding.

Fluorine(F) has 9 electrons and 7 valency electrons. To fulfil the octet rule, it readily accepts a single electron.

The correct chemical formula for the product of the reaction when beryllium and fluorine combine is BF₂.

This means 1 atom of beryllium combines with 2 atoms of fluorine to form beryllium fluoride. The beryllium give its 2 valency electrons to the 2 atoms of fluorine. The 2 atoms of fluorine will now have a valency electron of 8 each. The octet rule has been fulfilled at this point.

read more: brainly.com/question/24702809?referrer=searchResults

dangina [55]2 years ago
4 0

Answer:

BeF2

Explanation:

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How do you convert 212.26 grams of potassium phosphate to moles?
yaroslaw [1]

Answer: 1 mol of potassium phosphate.

Explanation:

Find the molar mass of potassium phosphate.

Equation of potassium phosphate = K3PO4

The molar mass of K = 39.10 g/mol, P = 30.97 g/mol, O = 16.00 g/mol (use periodic table for these values).

Then add them up together based off of the equation.

3(39.10 g/mol) + 30.97 g/mol + 4(16.00 g/mol) = 212.27 g/mol

Multiply the 212.26 grams by the molar mass (unit conversion method).

212.26 g*\frac{1 mol}{212.27 g} = 1.00 mol

There is 1 mol of potassium phosphate.

7 0
3 years ago
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Free_Kalibri [48]

Answer:

The remora benefits by gaining a measure of protection, and it feeds off of the remains of the meals of the larger fish.

Explanation:

They are both benefited

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Stoichiometry. Are my answers right?
OverLord2011 [107]

Answer:

Congratulations. Mostly correct.

Step-by-step explanation:

Part I. Gold

Moles of Au = 35.12 2g × 1/196.97 = 0.1783 mol Au

Atoms of Au = 0.1783 × 6.022 × 10²³/1 = 1.074 × 10²³ atoms Au

Part II. Sucrose

           Molar mass = 342.30 g/mol

Moles of C₁₂H₂₂O₁₁ = 1.202 g × 1/342.30

Moles of C₁₂H₂₂O₁₁ = 0.003 512 mol C₁₂H₂₂O₁₁

Moles of C = 0.003 512 × 12/1 = 0.042 14 mol C

Moles of H = 0.003 512 × 22/1 = 0.077 25 mol H

Moles of O = 0.003 512 × 11/1 = 0.038 63 mol O

Atoms of C = 0.042 14 × 6.022 × 10²³  = 2.538 × 10²² atoms C

Atoms of H = 0.077 25 × 6.022 × 10²³ = 4.652 × 10²² atoms H

Atoms of O = 0.038 63 × 6.022 × 10²³ = 2.326 × 10²² atoms O

<em>Minor Quibbles: </em>

You put the moles of sucrose in the molar mass slot.

You got the wrong exponents for the atoms of C, H, O.

You followed the rules for significant figures for gold, but not for sucrose.

6 0
4 years ago
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