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dlinn [17]
3 years ago
15

How many moles of HCI are needed to prepare 8.0 liters of a 4.0 M solution of HCI?

Chemistry
1 answer:
DerKrebs [107]3 years ago
6 0

Answer: 32 mol HCI

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in Liters

Now put all the given values in the formula of molarity, we get

4.0M=\frac{moles}{8.0L}

moles={4.0M\times 8.0L}=32mol

Therefore, the moles of HCI needed to prepare 8.0 liters of a 4.0 M solution of HCI are 32.

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Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

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