The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
So you know the slope is 2/3. We can write the equation y=mx+b and plug in the value we know to get y=(2/3)x+b. Since the line goes through the point, (-5,6) our equation must be true when the x and y value are plugged into the equation. We get (6)=(2/3)(-5)+b. Solving for b, we get 6=(-10/3)+b then b=28/3. This means our formula is y=(2/3)x+28/3
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Answer:
4th option
Step-by-step explanation:
7x(8x² - 4y² + 3y - 5) ← multiply each term in the parenthesis by 7x
= 56x³ - 28xy² + 21xy - 35x
Answer:
mean:
team 1: 41
team 2: 56
Step-by-step explanation:
add all numbers then divide by how many numbers
Answer:
If it's not too late by now, the answer is 19.9 