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3 years ago

Which group has high ionization energies but very weak electron affinities?

Chemistry

1 answer:

IrinaVladis [17]3 years ago

8 0

Answer:

the noble gases

Explanation:

The noble gases are characterized by their high ionization energies and low electron affinities. Potent oxidants are needed to oxidize the noble gases to form compounds in positive oxidation states. The noble gases have a closed-shell valence electron configuration.

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If 60.0 ml of a 1.5 m hcl solution is put into a flask and diluted with water to make 2.0 l of solution

77julia77 [94]

Answer:

The molarity of the diluted HCl solution: M₂ = 0.045 M

Explanation:

To find- the molarity of the diluted HCl solution (M₂)

Given- For original HCl solution-

Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L (∵ 1L = 1000 mL)

Then this original solution is diluted to a volume of 2 L

Thus for the diluted HCl solution-

The Volume of the diluted HCl solution: V₂ = 2 L

So the Molarity of the diluted HCl solution (M₂) can be calculated by the dilution equation:

$M_{1}\times V_{1} = M_{2}\times V_{2}$

$\Rightarrow M_{2} = \frac{M_{1}\times V_{1}}{V_{2}}$

$\Rightarrow M_{2} = \frac{1.5 M\times 0.06 L}{2 L} = 0.045 M$

Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M

7 0

3 years ago

How many grams of KCO3 are needed to make 20 L of a 2.5 M solution?

PolarNik [594]

Answer:

0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

Explanation:

7 0

3 years ago

What is the percent composition of Ca(OH)2? 37.7% Ca, 53.0% O, and 10.3% H 45.5% Ca, 38.2% O, and 16.3% H 54.0% Ca, 43.0% O, and

Naddik [55]

The molar mass of Calcium hydroxide is 74 g/mol

To find the percent composition we have to find the number of atoms of each element in the formula .

So there’s

Calcium - 1

Oxygen - 2

Hydrogen - 2

Then have to multiply the relative atomic mass of each element by the number of atoms

Ca - 40 g/mol x 1 = 40

O - 16 g/mol x 2 = 32

H - 1 g/mol x 2 = 2

Then To find percent composition of each element we have to divide the mass of each element in the formula by the relative molecular mass of calcium hydroxide

Ca - 40 / 74 x 100 % = 54.0%

O - 32 / 74 x 100 % = 43.2 %

H - 2 / 74 x 100 % = 2.7%

From the options given correct answer is 3rd option

54.0% Ca , 43.0% O and 2.7 % H

6 0

4 years ago

a 15.00 mL sample of an unknown HClO4 solution requires titration with 25.64 mL of 0.2000 M NaOH to reach equivalence point. wha

Veronika [31]

Answer:

V₁ = 0.342 M

Explanation:

Given data:

Volume of HClO₄ = 15.00 mL

Volume of NaOH = 25.64 mL

Molarity of NaOH = 0.2000 M

Molarity of HClO₄ = ?

Solution:

Formula:

M₁V₁ = M₂V₂

V₁ = M₂V₂ /M₁

V₁ = 0.2000 M ×25.64 mL /15.00 mL

V₁ = 5.128 M. mL /15.00 mL

V₁ = 0.342 M

5 0

3 years ago

The number of covalent bonds that an

amm1812

Answer: please make the question more understandable

Explanation:

4 0

3 years ago