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4 years ago

For the decomposition of nitramide in aqueous solution at 25C

Chemistry

1 answer:

JulsSmile [24]4 years ago

4 0

Answer:

0.001968 M min-1

Explanation:

NH2NO2(aq) --> N2O(g) + H2O(l)

[NH2NO2],M 0.978 0.476 0.232 0.113

time, min 0 255 510 765

The average rate of disappearance over the time period form t = 0 min to t = 255 min is given as;

Average rate = Change in concentration / time taken

Change in concentration = Final Concentration - Initial concentration

Change = 0.476 - 0.978 = 0.502

time taken = 255min - 0min = 255 min

Average rate = 0.502 / 255 = 0.001968 M min-1

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Please help with the equation in picture

matrenka [14]

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3 years ago

In France, grapes are 1.75 Euros per kilogram. What is the cost of grapes in dollars per pound if the exchange rate is 1.36 doll

Jet001 [13]

You want to convert Euros / kg to Dollars / pound

So you'll have to multiply the price (Euros / kg) by the exchange rate (Dollars / Euro) to get a number that has units of Dollars / kg.

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Then you have to multiply the number of kg in a pound (which has units of kg / pound) to get a number in units of Dollars / pound. This number is 2.2.

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3 0

3 years ago

HELP ASAP

Ghella [55]

potassium reacts the most vigorously.

7 0

3 years ago

The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42

denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

$k = Ae^{\frac{-Ea}{RT}}$

<u>Where:</u>

k: is the rate constant

A: is the frequency factor

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

$k_{1} = k_{2}$

$Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}$ (1)

By solving equation (1) for T₁ we have:

$T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C$

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!

4 0

4 years ago

The electronegativity values of carbon, hydrogen, and nitrogen are compared in the table.

Fofino [41]

Answer:

C. CH₄ is less than NH₃ because the NH bond is more polar than the CH bond

Explanation:

The intermolecular forces between ammonia is far stronger than for methane. Between the molecules of ammonia we have the presence of hydrogen bonds. This bond is absent in methane.

Hydrogen bonds are one of the strongest intermolecular forces. It is as a result of the electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom N, O and F of another molecule.

This strong interaction is absent in methane which has just dipole - dipole attraction.

The strength of the hydrogen bond depends on the electronegativity of the combining atoms.

5 0

3 years ago