There are two molecular orbitals in the CH2O or formaldehyde. These are designated by the two types of bonding involved. The first is the sigma bonding. It is the head-on overlap of electrons of the C and H atoms. The second molecular orbital is formed from the pi orbital bonding. This is a sideway overlap of electrons between C-O bonding.
Q1. TI (210/81Thallium)
Q2.
The answers are opposite from each other
<h2>Ionic bonds result from transferring of electrons</h2>
Explanation:
- Ionic bonds result from transferring of electrons.
- An ionic bond is also referred to as an electrovalent bond.
- The main reason for the formation of the bond is an electrostatic attraction between oppositely charged ions that are cation and anion in a chemical compound.
- The formation of such bonds occurs when the valence (outermost) electrons of one atom are transferred to another atom or the loss of electrons from one atom and gain of electrons of another atom.
- The atom that loses the electrons forms cation that is a positively charged ion.
- The atom that gains electrons forms an anion that is a negatively charged ion.
Answer:
25 mM Tris HCl and 0.1% w/v SDS
Explanation:
A <em>10X solution</em> is ten times more concentrated than a <em>1X solution</em>. The stock solution is generally more concentrated (10X) and for its use, a dilution is required. Thus, to prepare a buffer 1X from a 10X buffer, you have to perform a dilution in a factor of 10 (1 volume of 10X solution is taken and mixed with 9 volumes of water). In consequence, all the concentrations of the components are diluted 10 times. To calculate the final concentration of each component in the 1X solution, we simply divide the concentration into 10:
(250 mM Tris HCl)/10 = 25 mM Tris HCl
(1.92 M glycine)/10 = 0.192 M glycine
(1% w/v SDS)/10 = 0.1% w/v SDS
Therefore the final concentrations of Tris and SDS are 25 mM and 0.1% w/v, respectively.
