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Fudgin [204]
2 years ago
8

Margret claimed that she needed 5.45 moles of Potassium Chloride, KCl to complete her experiment. How many grams of KCl does she

need?
Chemistry
1 answer:
zubka84 [21]2 years ago
3 0

Answer:

loiuygfcx

Explanation:

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A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
3 years ago
A flashbulb of volume 1.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 18.0°C. How many grams of O2(g)
Lady bird [3.3K]

Answer:

0.0001637 mol

Explanation:

PV = nRT

Very important formula in chem

2.3 atm * 0.0017 L = n * 0.082057 * 291 K

= 0.0001637 mol O2

This concept is very important in chem, practice it.

7 0
3 years ago
I NEED HELP KNOW LAST QUESTION ON MY TEST
RoseWind [281]

Answer:  

Explanation: In my opinion  law is stated as fact because it is passes through and approved by many peoples but theory is an idea someone has and is not approved and is set on a base of beliefs.

8 0
3 years ago
Read 2 more answers
1 points)<br> You have 300 grams of Al2(CO3)3. How many moles are produced?
Pavlova-9 [17]

Answer:

0.5133805136 moles.

Explanation:

1 gram of Al2(Co3)3 equals 0.0017112683785004 moles, we need the amount of moles produced in 300 grams of Al2(CO3)3, so we have to multiply 1 gram of Al2(CO3)3 times 300: 0.0017112683785004 x 300, in conclusion,

300 grams of Al2(Co3)3 equals 0.5133805136.

5 0
2 years ago
Although fusion is an energetically favorable reaction for light nuclei, it does not occur under standard conditions on Earth be
hammer [34]
The best and most correct answer among the choices provided by your question is the first choice.

<span>Although fusion is an energetically favorable reaction for light nuclei, it does not occur under standard conditions on Earth because: fission reactions are always favored over fusion reactions.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Read 2 more answers
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