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melisa1 [442]
3 years ago
5

Need help with this question, anybody .. -20 points :)

Chemistry
1 answer:
prisoha [69]3 years ago
8 0
I think that its D, i did this question before and thats what i got and it was right
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Which element must be present in an avid
Yuliya22 [10]
WHat? May you please rephrase your question? I think you meant in an organic compound? The answer to that would be CARBON.
4 0
3 years ago
A 1.87 mol sample of Ar gas is confined in a 45.5 liter container at 23.6 °C.
lora16 [44]

Answer:

a. increase

Explanation:

Based on the kinetic molecular theory of gases, the average kinetic energy of the system will increase.

  • The average kinetic energy is heat
  • If temperature increases, heat of a system will also rise.
  • According the kinetic molecular theory "the temperature of the gas is a measure of the average kinetic energy of the molecules"

Therefore, due to the increase in temperature, the average kinetic energy of the system increases.

5 0
3 years ago
A solution has a [Ag+(aq)] of 0.01 M. The chloride concentration in solution is 1 x 10-5 M. Based on the following reaction, ans
earnstyle [38]
 The value  of current  solubility  product  is calculated as  below

K =  (Ag+)( Cl-)

 Ag+  =  0.01 M
Cl-= 1 x10^-5M

K is therefore = 1 x10^-5 x 0.01 = 1 x10  ^ -7 M

The K obtained is greater  than  Ksp

that is    K>  KSp
 1x10^-7 >  1.7 x10 ^-10


will  precipitation  of AgCl form?

yes  the precipitation  of AgCl  will  be formed   since   K> KSP


7 0
4 years ago
(science)
emmainna [20.7K]
The answer is simulus check baby girl
4 0
3 years ago
Read 2 more answers
Smooth muscle myosin is a motor protein that plays a crucial role in the contraction of smooth muscle. If this protein has a mol
zysi [14]

Answer: Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass, occupies 22.4 L at STP  contains avogadro's number (6.023\times 10^{23}) of particles.

Molecular mass of protein = 480,000 g/mol

Thus 1 mole of protein weighs = 480,000 g

So 27 moles of protein weighs = \frac{480,000}{1}\times 27=12960000g

Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams

6 0
4 years ago
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