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Neko [114]
3 years ago
9

Match the element with its number of valence electrons. Match Term Definition: Helium Aluminum Fluorine Sodium A) 1 B) 2 C) 3 D)

7
Chemistry
2 answers:
wariber [46]3 years ago
5 0

Helium- 2

Aluminum- 3

Fluorine- 7

Sodium- 1

Hope I helped.

vampirchik [111]3 years ago
3 0

<u>Explanation:</u>

Valence electrons are defined as the electrons that are present in the outermost shell of an atom.

  • Helium is the 2nd element of the periodic table having electronic configuration of 1s^2

This element has 2 electrons in its outermost shell. So, it has 2 valence electrons. The correct answer is Option B.

  • Aluminium is the 13th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^1

This element has 3 electrons in its outermost shell. So, it has 3 valence electrons. The correct answer is Option C.

  • Fluorine is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

This element has 7 electrons in its outermost shell. So, it has 7 valence electrons. The correct answer is Option D.

  • Sodium is the 11th element of the periodic table having electronic configuration of 1s^22s^22p^63s^1

This element has 1 electron in its outermost shell. So, it has 1 valence electron. The correct answer is Option A.

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4 0
3 years ago
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What is the mass of oxygen in 3.34 g of potassium permanganate?
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Answer:

1.35 g

Explanation:

Data Given:

mass of Potassium Permagnate (KMnO₄) = 3.34 g

Mass of Oxygen: ?

Solution:

First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)

So,

Molar Mass of KMnO₄ = 39 + 55 + 4(16)

Molar Mass of KMnO₄ = 158 g/mol

Calculate the mole percent composition of  Oxygen in Potassium Permagnate (KMnO₄).

Mass contributed by Oxygen (O) = 4 (16) = 64 g

Since the percentage of compound is 100

So,

                        Percent of Oxygen (O) = 64 / 158 x 100

                        Percent of Oxygen (O) = 40.5 %

It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.

So,

for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be

                  mass of Oxygen (O) = 0.405 x 3.34 g

                  mass of Oxygen (O) = 1.35 g

5 0
3 years ago
Why is carbon dioxide used in fire extinguisher?
rjkz [21]
As Fire needs oxygen to burn, Carbon Dioxide Covers the fire like an blanket and cuts the contact of fire to the oxygen present in the air, So Fire stops burning.That is why Carbon Dioxide is Considere as the best Fire Extinguisher.
3 0
3 years ago
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What is the transition interval for phenol red? 24 a. pH 3.1-4.4 b. pH 6.4-8.0 c. pH 6.2-7.6 d. pH 8.0-10.0
alukav5142 [94]

Answer:

The correct option is: b. pH 6.4-8.0

Explanation:

Phenol red is a weak acid that is used as a pH indicator and exists in the form of stable red crystals.

<u>The color of the phenol red solution changes from yellow to red when the change in pH is observed. The color of phenol red transitions from yellow to red when the pH is 6.8 - 8.2 or 6.4 - 8.0</u>

Above the pH of 8.2, the phenol red solution turns a bright pink in color.

6 0
3 years ago
If you have 150 grams of s8, how many moles of so2 can you make?
ruslelena [56]

Answer : You can make 4.68 moles of SO₂

Explanation:

Step 1 : Write balanced equation.

S₈ can combine with oxygen to form SO₂ gas. The balanced equation for this reaction is written below.

S_{8}  + 8 O_{2} \rightarrow 8 SO_{2}

Step 2 : Find moles of S₈

The formula to calculate mol is

mole = \frac{grams}{MolarMass}

Molar mass of S₈ is 256.5 g/mol

mole = \frac{150grams}{256.5 g/mol}

mole = 0.585 mol

we have 0.585 mol of S₈

Step 3: Use mole ratio to find moles of SO₂

The mole ratio of S₈ and SO₂ can be found using balanced equation which is 1:8

That means 1 mol of S₈ can form 8 moles of SO₂.

Let us use this as a conversion factor to find moles of SO₂

0.585 mol (S_{8}) \times \frac{8 mol (SO_{2})}{1 mol (S_{8})}  = 4.68 mol

Therefore we have 4.68 moles of SO₂

4 0
3 years ago
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