Answer:
Q = 1267720 J
Explanation:
∴ QH2O = mCpΔT
∴ m H2O = 500 g
∴ Cp H2O = 4.186 J/g°C = 4.183 E-3 KJ/g°C
∴ ΔT = 120 - 50 = 70°C
⇒ QH2O = (500 g)(4.183 E-3 KJ/g°C)(70°C) = 146.51 KJ
∴ ΔHv H2O = 40.7 KJ/mol
moles H2O:
∴ mm H2O = 18.015 g/mol
⇒ moles H2O = (500 g)(mol/18.015 g) = 27.548 mol H2O
⇒ ΔHv H2O = (40.7 KJ/mol)(27.548 mol) = 1121.21 KJ
⇒ Qt = 146.51 KJ + 1121.21 KJ = 1267.72 KJ = 1267720 J
The grams of solute are required.
The mass of solute is 3.5 g
c = Molarity = 0.1 M
M = Molar mass = 350 g/mol
V = Volume of solution = 100 mL = 0.1 L
n = Number of moles
m = Mass of solute
Molarity is given by

Molar mass is given by

The mass of solute is 3.5 g
Learn more:
brainly.com/question/16633651?referrer=searchResults
A physical change has occured, Boiling water is a physical change not a chemical one, now if you're talking about the electric current, that had not changes either. it may rearrange the molecules, but it does not change the fundamental properties of the substance.
A gas produced in a chemical reaction can be collected by water displacement. Because the gas is collected over water, it is not pure but is mixed with vapor from the evaporation of the water. Dalton's law can be used to calculate the amount of the desired gas by subtracting the contribution of the water vapor.
Answer:
52.206 kg
Explanation:
From the given information:
Mass of hexane C6H14 = 
= 7391.9 g
Mass of octane C8H18 = 
= 2682.7 g
Mass of decane C10H22 = 
= 9225.4 g
However, recall that:
number of moles of an atom = mass/molar mass
∴
For hexane, no of moles = 7391.9 g/86.18 g/mol
= 85.77 moles
For octane, no of moles = 2682.7 g/114.23 g/mol
= 23.49 moles
For decane, no of moles = 9225.4 g/142.29 g/mol
= 64.84 moles
Therefore:
number of moles of CO2 produced = (6 × 85.77)+(23.49)+(10×64.84) moles
= 1186.51 moles
Finally, the mass of CO2 produced is:
= 1186.51 mol × 44 g/mol
= 52206.44 g
= 52.206 kg