Ask question

Ask question

All categories

3 years ago

6

In a water solution, HCl and NaOH react to form H2O and NaCl. Radium-226 undergoes alpha decay to form radon-222. The temperatur

e of both of these reactions is increased. Which of the following statements is true?A) The rate of the chemical reaction increases, but the rate of the nuclear reaction remains the same.
B) The rate of the nuclear reaction increases, but the rate of the chemical reaction remains the same.
C) The rates of both reactions increase.
D) The rates of both reactions remain the same.

2 answers:

ira [324]3 years ago

7 0

Answer: B.

The rate of the nuclear reaction increases, but the rate of the chemical reaction remains the same

Explanation:

Oxana [17]3 years ago

7 0

The answer is B because the rate of the nuclear reaction increases, but the rate of the chemical reaction will not change.

You might be interested in

.Which of the following is true about elements?

Ludmilka [50]

Answer:

C

Explanation:

6 0

2 years ago

Read 2 more answers

What is the pOH of a solution with a pH of 8

meriva

Is 5 the answer is 5

6 0

3 years ago

A solution of NaF is added dropwise to a solution that is 0.0144 M in Ba 2 . When the concentration of F - exceeds __________ M,

Stella [2.4K]

Answer:

When [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate

Explanation:

Ksp of BaF₂ is:

BaF₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)

Ksp = 1.7x10⁻⁶ = [Ba²⁺] [F⁻]²

The solution will produce BaF₂(s) -precipitate- just when [Ba²⁺] [F⁻]² > 1.7x10⁻⁶.

As the concentration of [Ba²⁺] is 0.0144M, the product [Ba²⁺] [F⁻]² will be equal to ksp just when:

1.7x10⁻⁶ = [Ba²⁺] [F⁻]²

1.7x10⁻⁶ = [0.0144M] [F⁻]²

1.18x10⁻⁴ = [F⁻]²

0.0109M = [F⁻]

That means, when [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate

5 0

3 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

3 years ago

jeka94

The largest risks while designing a model to withstand a village include that the model does not mitigate the effects of the tsunami or only mitigates the effects partially, which would cause damages to the homes.

Designing a model to withstand the effect of any natural phenomenon such as an earthquake, fire or tsunami is not an easy task and will require the following cycle:

Designing the model.
Testing the model.
Making changes or designing a new model.

In the case of a model for tsunamis, it is likely the following problems occur:

The model does not protect the houses from tsunamis.
The model does not protect the houses completely.

This would lead to negative effects such as:

Damages in the houses.
Dead or injured people.
Destruction of infrastrcture.

Note: This question is incomplete because the context is missing; here is the missing part.

Protecting Your Model Village from Tsunamis this task, you will design a model village to withstand the effects of a tsunami.

Learn more about tsunami in: brainly.com/question/1126317

6 0

2 years ago