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iren [92.7K]
2 years ago
13

Can someone answer this question real quick please?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0

Answer:

open circle btw

Step-by-step explanation:

step 1: go to the right where the 3 is

step 2: go to the little dash the 1st one on the right of the 3

step 3: circle the dash and make an arrow going to the right

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What is the center of a circle whose equation is x2 y2 – 12x – 2y 12 = 0? (–12, –2) (–6, –1) (6, 1) (12, 2)
lora16 [44]

The center of a circle whose equation is x^2 +y^2 – 12x – 2y  +12 = 0 is (6,1)

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as:

x^2 + y^2 + 2gx + 2fy + c = 0

where:

(-g, -f) is the centre of the circle

Given the equations

x^2 +y^2 – 12x – 2y  +12 = 0

Compare

2gx = -12x

g = -6

Simiarly

-2y = 2fy

f = -1

Centre = (6, 1)

Hence the  center of a circle whose equation is x^2 +y^2 – 12x – 2y  +12 = 0 is (6,1)

Learn more on equation of a circle here: brainly.com/question/1506955

8 0
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Which transformation(s) were used to go from the parent graph (red) to the transformed graph (blue)? Check all that apply!
UNO [17]
<h3>2 Answers: </h3><h3>Choice B) Shift down</h3><h3>Choice C) Shift right</h3>

===================================================

Explanation:

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To do so, we need to shift down and to the right (in either order).

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We do not apply any dilations. The red and blue segments are the same length because translations preserve distance. All we're effectively doing is moving the red segment to land on the blue segment. This means no vertical or horizontal stretches are done. The same can be said about compressions as well.

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