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Shalnov [3]
3 years ago
6

Solve -2x - 5 = 4 for x.

Mathematics
2 answers:
MrRa [10]3 years ago
7 0

Step-by-step explanation:

-2x - 5 = 4

-2x = 9

x= -4.5

hope it helps

joja [24]3 years ago
6 0

Answer:

<u>-2x </u><u>-</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>4</u>

<u>-2x </u><u>=</u><u> </u><u>4</u><u> </u><u>-</u><u> </u><u>-</u><u> </u><u>5</u>

<u>-2x </u><u>=</u><u> </u><u>9</u>

<u>x=</u><u> </u><u>9</u><u>/</u><u>2</u>

<u>x </u><u>=</u><u> </u><u>4</u><u>.</u><u>5</u>

<h2><u>I </u><u>HOPE</u><u> IT</u><u> IS</u><u> HELPFUL</u></h2>

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olya-2409 [2.1K]
Assuming that we are solving for x when each equation is equal to zero, the solutions are:

1) -.4
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7 0
2 years ago
solve the equation by completing the square. x^2 -6x -21=0 if the solution is not a real number enter no solution (ANSWER -2.48
Alexus [3.1K]

Answer:

see explanation

Step-by-step explanation:

given x² - 6x - 21 = 0 ( add 21 to both sides )

x² - 6x = 21

to complete the square

• add ( half the coefficient of the x-term)² to both sides

x² + 2 (- 3)x +9 = 21 + 9

(x - 3)² = 30 ( take the square root of both sides )

x - 3 = ± \sqrt{30} ( add 3 to both sides )

x = 3 ± \sqrt{30}

x = 3 - \sqrt{30} = - 2.48 ( to 2 dec. places ) or

x = 3 + \sqrt{30} = 8.48 ( to 2 dec. places )


3 0
2 years ago
If TRAP is an isosceles trapezoid what is the value of x
rewona [7]

Answer:

B

Step-by-step explanation:

In an isosceles trapezoid any lower base angle is supplementary to any upper base angle, thus

6x + 2x + 4 = 180, that is

8x + 4 = 180 ( subtract 4 from both sides )

8x = 176 ( divide both sides by 8 )

x = 22 → B

4 0
3 years ago
Use the method of dividing prime factors to find the greatest common factor of 16, 120, and 216.
lawyer [7]
I hope this helps you

4 0
3 years ago
Solve for b<br> 2(-2b+3)=9
Alexxx [7]

Answer:

b=-3/4 or b=-0.75

Step-by-step explanation:

2(-2b+3)=9

2b+3=\cfrac{9}{2}

-2b=\cfrac{9}{3} -3

-2b=\cfrac{3}{2}

b=-\cfrac{\frac{3}{2} }{2}

b=-\cfrac{3}{2\times 2}

b=-\cfrac{3}{4}

Hope it helps! :)

7 0
2 years ago
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