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Vadim26 [7]
2 years ago
9

Look at pic and solve

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
5 0

Answer:

Yes it can be solved.

Step-by-step explanation:

I did this stuff in like 4th grade lollll

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Use the pythagorean Theorem to prove the three sides of the triangle are the three sides of a right triangle. Show all of your w
weeeeeb [17]

Answer:

2^{2} + (2\sqrt{3}) ^{2} = 4 + 4 * 3 = 16 = 4^{2}

Step-by-step explanation:

The Pythagorean Theorem states that the two shorter sides of a right triangle squared and added together will equal the longest side (hypotenuse) of the right triangle squared. The longest side of this right triangle is 4, 4 squared is 16. The two shorter sides of the right triangle are 2 and 2\sqrt{3}, squared individually would be 4 and 12, and added together they also equal 16. These sides are a valid input for the Pythagorean Theorem, so these three sides are the sides of a right triangle. 2 and 2\sqrt{3} being the legs of the right triangle, and 4 being the hypotenuse.

6 0
3 years ago
Which transformation on the coordinate plane is a dilation?
Kaylis [27]

Answer:

It is the third one

Step-by-step explanation:

if that was the question even, I chose this as dilation is basically just getting bigger or smaller but without rotation,sliding, and none of the sides should be changing

6 0
2 years ago
13(10 + 2) could be used to simplify which of the following problems?
Veseljchak [2.6K]
Well first you need to show the rest of the problems before i can truely help you sorry.
6 0
2 years ago
I need the whole solution
ddd [48]

Confused what the question is. Are you looking for the product or the zeroes?

If you are looking for the product, then:

Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)

= sec² + sec²csc² - 1 + csc²

= sec²csc² + sec² + csc² - 1

= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)

= sec²csc²

Answer: sec²csc²

***************************************************

If you are looking for the zeroes, then:

Using the zero product property, set each factor equal to zero and solve.

<u>First factor:</u>

sec²Θ - 1 = 0

sec²Θ = 1

secΘ = 1, -1

remember that secΘ is \frac{1}{cos}

\frac{1}{cos} = 1 \frac{1}{cos} = -1

cross multiply to get:

cosΘ = 1 cosΘ = -1

use the unit circle (or a calculator) to find that Θ = 0 and π

<u>Second factor:</u>

1 - csc²Θ = 0

1 = csc²Θ

1, -1 = cscΘ

remember that cscΘ is \frac{1}{sin}

\frac{1}{sin} = 1 \frac{1}{sin} = -1

cross multiply to get:

sinΘ = 1 sinΘ = -1

use the unit circle (or a calculator) to find that Θ = \frac{\pi}{2} and \frac{3\pi}{2}

Answer: 0, π, \frac{\pi}{2} , \frac{3\pi}{2}

7 0
3 years ago
Solve for x -(2x+5)+14=22
Gala2k [10]

Hey there!☺

Answer:\boxed{x=\frac{-13}{2}}

Explanation:

-(2x+5)+14=22 Equation

−(2x+5)+14=22  Simplify both sides

−2x + −5 + 14 = 22 Distribute

(−2x) + (−5+14) = 22 Combine Like Terms

-2x + 9 = 22

-2x + 9 - 9 = 22 - 9 Subtract 9 from both sides

-2x = 13

-2x/-2 = 13/-2

-13/2 Add the negative to 13

x = -13/2

Hope this helps!

7 0
3 years ago
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