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Dmitrij [34]
2 years ago
11

.−3(4x + 3) + 4(6x + 1) = 43 What is the answer?

Mathematics
1 answer:
gtnhenbr [62]2 years ago
6 0

Answer:

43

Step-by-step explanation:

DO the math

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Write an equation and solve:
11Alexandr11 [23.1K]

Answer

Find out  how many  months will it take for Jeff to weigh the same as Darius .

To prove

As given

Jeff and Darius are trying to gain weight for the football team.

Jeff weighs 120 pounds and is gaining  ten pounds per month.

Darius weighs 150 pounds and is gaining 4 pounds per month.

m = represented the number of months will taken by the Jeff to weigh the same as Darius .

Than the equation become in the form

120 + 10m = 150 +4m

150 - 120 = 10m - 4m

30 = 6m

m = \frac{30}{6}

m = 5 months

Therefore in 5 months  will it take for Jeff to weigh the same as Darius.

4 0
3 years ago
Use the quadratic formula to solve the equation x^2-7x-6=0
olganol [36]

Answer:

\frac{7\pm\sqrt{73}} {2}

Explanation:

We have been given with the quadratic equation x^2-7x-6=0

We have general formula to find the roots of a quadratic equation first we find the discriminant with formula

D=b^{2}-4ac

and after that to find the variable suppose x we have the formula

x=\frac{-b\pm\sqrt{D}} {2a}

And general quadratic equation is

ax^2+bx+c=0

On comparing the given quadratic equation with genral quadratic equation we will have values

a=1, b=-7 and c=-6

After substituting these values in the formula we will get  

D=(-7)^2-4(1)(-6)={73}

After substituting in the formula to find x we will get

\frac{-(-7)\pm\sqrt{73}} {2}= \frac{7\pm\sqrt{73}} {2}

4 0
3 years ago
Read 2 more answers
Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
3 years ago
The last part of question says find temperature at 11pm
andrezito [222]

Answer:

3 deg C

Step-by-step explanation:

Start with -8 deg and add 11 deg.

-8 + 11 = 3

Answer: 3 deg C

5 0
2 years ago
Read 2 more answers
Answer this please. Thank you! Worth 10 points as well.
nlexa [21]
The probability that the next 4 winners will all be 7th grade students is 3/4
3 0
3 years ago
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