Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
Subtraction property ; x = 3.25
Division property ; - 6
multiplication property ; - 125
Addition property ; 13
Step-by-step explanation:
A.)
x + 3.75 = 7
Using the subtraction property : subtract 3.75 from both sides
x + 3.75 - 3.75 = 7 - 3.75
x = 3.25
B. )
–3b = 18
According to the division property :
Divide both sides by - 3
-3b / - 3 = 18 / - 3
b = - 6
C.)
m/5 = - 25
Using the multiplication property :
m/5 * 5 = - 25 * 5
m = - 125
D.)
m – 4 = 9
Using the addition property :
Add 4 to both sides :
m - 4 + 4 = 9 + 4
m = 13
Answer:
0 is greater
Step-by-step explanation:
When comparing the values of two numbers, you can use a number line to determine which number is greater.
Answer:
B is the answer bruh
Step-by-step explanation:
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