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tino4ka555 [31]

4 years ago

6

Can you please explain why?

1 answer:

Sauron [17]4 years ago

8 0

Explain what? Im happy to help!

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Heat is added to a 200.-gram sample of H2O(s) to melt the sample at 0°C. Then the resulting H2O (image) is heated to a final tem

pochemuha

You are given 200 grams of H2O(s) at an initial temperature of 0°C. you are also given the final temperature of water after heating at 65°C. You are required to get the total amount of heat to melt the sample. The specific heat capacity, cp, of water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for heat, Q, is

Q = m(cp)(T2-T1)
Q = 200g(4.186 J/g-°C )(65°C - 0°C)
<u>Q = 54,418J</u>

3 0

3 years ago

Read 2 more answers

If you have a gas sample with an initial pressure of 16 atm, an initial volume of 20 L and a temperature of 500 K, what will the

DiKsa [7]

Answer:

T₂ = 218.75 K

Explanation:

Given data:

Initial volume = 20 L

Initial pressure = 16 atm

Initial temperature = 500 K

Final temperature = ?

Final volume = 35 L

Final pressure = 4 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂ T₁/ P₁V₁

T₂ = 4 atm × 35 L × 500 K / 16 atm × 20 L

T₂ = 70000 atm .L. K / 320 atm.L

T₂ = 218.75 K

5 0

3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0

3 years ago

1. What is the percent composition of CaCO₃? Show your work.

kaheart [24]

Hai

<span> What is the mass of sodium in 50 grams of salt?
</span>
2000mg

6 0

3 years ago

Read 2 more answers

Which of these are highest in fat?<br><br> Almonds<br> Butter<br> Sesame oil

agasfer [191]

Answer:

almonds and sesame oil have the same amount of fat.

Explanation:

Almonds: 14 g

Butter: 12 g

Sesame Oil: 14 g

7 0

3 years ago