Answer:
2.8248 g
Explanation:
First, consider the balanced chemical equation:
Then we calculate the number of moles in 4.11 g of citric acid:
n(citric acid)=
According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.
so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol
mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol
= 2.8248 g