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3 years ago

A taxi driver charges an initial fee of $2.00 plus $0.30 per mile. What is the independent variable quantity in this situation?

1 answer:

5 0

Answer: The .30 per mile is the independent, because it is manipulated, and changed throughout. DRY MIX : Dependent, Responding, Y axis. Manipulated, Independent, X axis.

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How do you simplify 9/8?

Mademuasel [1]

Answer:

1 1/8

Step-by-step explanation:

divide 9 and 8 and u get ur answer Hoped I helped im Eve btw. Have a great day and consider marking this brainliest if you do thank you in advanced!

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2 years ago

5kg to 5212g increase or decrease

Bingel [31]

Answer:

increase

Step-by-step explanation:

5kg to 5212g

First, Let's put these numbers into similar units

1kg=1000g, so

5kg=5000g

And 5000g<5212g

Therefore, it is an increase

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2 years ago

What is the value of LN

bija089 [108]

LN=

$ln = jh \div 2 = 14 \div 2 = 7$

=> LN=7

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2 years ago

Mr. Lawson parked his car in a parking garage 33 feet below street level. He

xz_007 [3.2K]

Step-by-step explanation:

Subtraction

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2 years ago

Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?

Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}$

so we're really looking for a line whose slope is 3 and runs through (1,5)

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2$

4 0

2 years ago