Birthday polynomial My birthday is November 1, 2004

Mathematics

1 answer:

miss Akunina [59]2 years ago

4 0

Answer: -939080938

Step-by-step explanation:

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There were 8 red cars and 12 blue cars in the parking lot what is the ratio of the number of red cars to number of blue cars

salantis [7]

Answer:

2 : 3

Step-by-step explanation:

<em>Hello fellow human!</em>

red : blue - 8 : 12

The ratio is divisible by 4 - (8/4) = 2 ; (12/4) = 3

Hence, 2 : 3

8 0

2 years ago

Angle MNO is formed by segments MN and NO on the following coordinate grid:

Eva8 [605]

Answer:

I am 90% sure that the answer is M'N'O' is 90*

Step-by-step explanation:

A line segment MN is shown as M = -1,1 and N= -5,4 this makes a diagonal line across the grid. Another line segment NO is shown with O as ordered pair negative 1, 4. Angle MNO is rotated 90 degrees counterclockwise about the origin to form angle M′N′O′. this is where the angles meet, Rotating the shape (or the angles) does not change the degree of the angle of the shape. I am 99% sure that an 90* angle would be formed. but im just in middle school so what do i know?

6 0

3 years ago

Read 2 more answers

Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com

fredd [130]

$f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}$

$f$ has critical points where the derivative is 0:

$2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1$

The second derivative is

$f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}$

and $f''(-1)=\frac2e>0$ , which indicates a local minimum at $x=-1$ with a value of $f(-1)=\frac1e$ .

At the endpoints of [-2, 2], we have $f(-2)=1$ and $f(2)=e^8$ , so that $f$ has an absolute minimum of $\frac1e$ and an absolute maximum of $e^8$ on [-2, 2].