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alexandr1967 [171]
2 years ago
14

Thomas claims: The school bus will either be on time or late. The probability that it will be on time is therefore 0.5

Mathematics
1 answer:
Veronika [31]2 years ago
3 0

The answer is yes

PLEASEEEEE MARK ME AS THE BESTT LOLL

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In a study, 42% of adults questioned reported that their health was excellent. A researcher wishes to study the health of people
kobusy [5.1K]

Answer:

The probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.6483.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of adults questioned reported that their health was excellent.

A random sample of <em>n</em> = 11 adults are selected randomly selected from an area a nuclear power plant.

Of these 11 adults <em>X</em> = 3 reported that their health was excellent.

The proportion of adults who reported that their health was excellent is:

p=\frac{X}{n}=\frac{3}{11}

An adult's health condition is not affected by others, i.e. they are independent.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 11 and <em>p</em> = \frac{3}{11}.

The probability mass function of <em>X</em> is:

P(X=x)={11\choose x}(\frac{3}{11})^{x}(1-\frac{3}{11})^{11-x};\ x=0,1,2,3...

Compute the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health as follows:

P (X ≤ 3) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)

              =\sum\limits^{3}_{x=0}{{11\choose x}(\frac{3}{11})^{x}(1-\frac{3}{11})^{11-x}}\\=0.02998+0.12385+0.23254+0.26197\\=0.64834\\\approx 0.6483

Thus, the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.6483.

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