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Anna [14]
2 years ago
9

in terms of the wavelength of the sound wave, about how far below the open end of the resonance tube is the first resonant posit

ion?
Physics
1 answer:
notka56 [123]2 years ago
8 0

The first resonant position below the open end of the resonance tube is; <em><u>one-quarter of the wavelength</u></em>

In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.

However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.

This means that the standing wave will have one-quarter of the wavelength in the test tube.

Thus;

L = ¼λ

Read more at; brainly.com/question/17086525

You might be interested in
ustapha Jones is speeding on the interstate in his Ferrari at 231km/hr when he passes a police car at rest . If the cop accelera
Lena [83]

Answer:

461 km/h

Explanation:

In order to solve this problem we must first sketch a drawing of what the situation looks like so we can better visualize it. (See attached picture).

We have two situations there, the first one is Mustapha's car that is traveling at a constant speed of 231km/hr.

The second situation is the police that is accelerating from rest until he reaches Mustapha. (We are going to suppose the acceleration is constant and that he will not stop accelerating until he reaches Mustapha). He has an acceleration of 15m/s^{2}.

We want to find what the final velocity of the police is at the time he reaches Mustapha. From this we can imply that the displacement x will be the same for both particles.

So let's model the first situation.

The displacement of Mustapha can be found by using the following equation:

V_{M}=\frac{x}{t}

when solving the equation for the displacement x we get that it will be:

x=V_{M}t

Now let's model the displacement of the cop. Since the cop has a constant acceleration, we can model his displacement with the following formula.

x=V_{0}t+\frac{1}{2}at^{2}

Since the initial velocity of the cop is zero, we can get rid of that part of the equation leaving us with:

x=\frac{1}{2}at^{2}

We can now set both equations equal to each other so we get:

\frac{1}{2}at^{2}=V_{M}t

When solving this for t, we get that:

t=\frac{2V_{M}}{a}  (let's call this equation 1)

Now, we know the cop has constant acceleration, so we can model it with the following formula too:

a=\frac{V_{f}-V_{0}}{t}

since the initial velocity of the cop is zero, we can get rid of that here too, so we get the following formula:

a=\frac{V_{f}}{t}

when solving for the final velocity, we get that:

V_{f}=at  (let's call this equation 2)

when substituting equation 1 into equation 2 we get:

V_{f}=a(\frac{2V_{M}}{a})

we can now cancel a leaving us with:

V_{f}=2V_{M}

This tells us that the final velocity of the cop will not depend on his acceleration. (This is only if the acceleration is constant all the time) So we get that the final velocity of the cop is:

V_{f}=2(231km/hr)

so

V_{f}=461km/hr

which is our answer.

8 0
3 years ago
Alex swims at an average speed of 4.5 m/s how far does he swim in one minute 24 seconds
Zepler [3.9K]

Answer:

378

Explanation:

60 seconds in one minute

add the 24 seconds

multiply it by 4.5

60 + 24 = 84

4.5 x 84 = 378

8 0
3 years ago
When two objects interact, the change in momentum of the first object is ______ the change in momentum of the second object.
Mariulka [41]

Answer:

A. Equal to and Opposite

Explanation:

           when there is no External force acting on the system of bodies then Net momentum of the system is Conserved .

        Given that there are 2 bodies

         Let  P₁ as first object's momentum

                  P₂ as second object's momentum.

                  Total Momentum =P₁ + P₂

           As there is no external force acying on the system

                 Change in the Total momentum is zero

so,

                  0 = Δ P₁ + ΔP₂

                   ΔP₂ = -ΔP₁

                   negative sign indicates opposite direction.

                       Both are of equal magnitude.

6 0
4 years ago
What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t
Nadya [2.5K]

Answer:

The awnser is d

Explanation:

i know cause i took the test

6 0
3 years ago
Read 2 more answers
A 5.0-kilogram box is sliding across a level floor. The box is acted upon by a force of 27 newtons east and a frictional force o
marshall27 [118]

Answer:

The magnitude of the acceleration of the box is 2 m/s².

Explanation:

Given:

Mass of the box, m=5.0 kg

Force acting towards east, F=27 N

Frictional force acting towards west, f=17 N

Let the acceleration be a m/s².

Now, net force acting on the box towards east is given as:

F_{net}=F-f=27-17=10\textrm{ N}

From Newton's second law of motion,

F_{net}=ma\\10=5.0\times a\\a=\frac{10}{5.0}=2\textrm{ }m/s^2

Therefore, the magnitude of the acceleration of the box is 2 m/s².

6 0
3 years ago
Read 2 more answers
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