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dimaraw [331]
3 years ago
12

What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t

Physics
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:

The awnser is d

Explanation:

i know cause i took the test

erastovalidia [21]3 years ago
5 0

Answer:

D  34 m/s east

Explanation:

Took the test got 100%

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Starting from rest, a basketball rolls from top of a hill to the bottom, reaching a translational speed of 6.8 m/s. Ignore frict
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Answer:

Explanation:

for baseball

(a) Let the mass of the baseball is m.

radius of baseball is r.

Total kinetic energy of the baseball, T = rotational kinetic energy + translational kinetic energy

T = 0.5 Iω² + 0.5 mv²

Where, I be the moment of inertia and ω be the angular speed.

ω = v/r

T = 0.5 x 2/3 mr² x v²/r² + 0.5 mv²

T = 0.83 mv²

According to the conservation of energy, the total kinetic energy at the bottom is equal to the total potential energy at the top.

m g h = 0.83 mv²

where, h be the height of the top of the hill.

9.8 x h = 0.83 x 6.8 x 6.8

h = 3.93 m

(b) Let the velocity of juice can is v'.

moment of inertia of the juice can = 1/2mr²

So, total kinetic energy

T = 0.5 x I x ω² + 0.5 mv²

T = 0.5 x 0.5 x m x r² x v²/r² + 0.5 mv²

m g h = 0.75 mv²

9.8 x 3.93 = 0.75 v²

v = 7.2 m/s

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3 years ago
5 WILL PAY YOU CASH APP IF YOU ANSWER
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Answer:

Dogs make good therapy pets because they usually crave lots of attention and affection.

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scientists use critical thinking skills throughout the process of research or information a student noticed that their energy le
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The latin word (Cirro) mean that the clouds are in high level <br><br> True of false?
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False

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Therefore, the answer is False.

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3 years ago
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A larger object is made of two balls separated by a massless rigid rod that is 1.5 m long. The mass of the red ball at one end i
lions [1.4K]

Answer:

The speed of the 1 kg red ball 8.04 m/s .

Explanation:

Given :

Separation between rods , d = 1.5 m .

Mass of the red ball is 1 kg .

Mass of the orange ball is 5.7 kg .

Angular velocity , \omega=1\ rev/s = 2\pi\ rad/s .

Now , distance of center of mass  from red ball is :

r =\dfrac{0\times 1+1.5\times 5.7}{1+5.7}\\\\r = 1.28\ m

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v=\omega r\\\\v=2 \times \pi \times  1.28\\\\v=8.04\ m/s

Hence , this is the required solution .

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