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dimaraw [331]
3 years ago
12

What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t

Physics
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:

The awnser is d

Explanation:

i know cause i took the test

erastovalidia [21]3 years ago
5 0

Answer:

D  34 m/s east

Explanation:

Took the test got 100%

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Momentum is a vector quantity because it includes velocity, which is also a
zvonat [6]

Answer: A; True

Explanation: Momentum is known to be a vector quality, and thus has been proven by modern scientists and resulting in this answer being true.

Hope this helps <3

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-Carrie

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7 0
3 years ago
Heartburn is a form of indigestion felt as a burning sensation in the chest when stomach acid comes back up into the esophagus.
xenn [34]
The antacid is basic so it neutralizes acidity or lowers it. Then if it goes into the esophagus, it's not as strong and it doesn't hurt, and it also calms your stomach because the acidity in your stomach is also lower. Antacids are therefore taken by many people, especially as they grow older and things like heartburn become more common.
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3 years ago
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Which statement describes a question that can be answered by a scientific
goblinko [34]
It’s d! hope I can help
4 0
4 years ago
Read 2 more answers
A Sonometer wire of length
Scrat [10]

Answer:

-75 cm

Explanation:

At l ; F = 350 Hz

At l + 15 cm ; F = 280 Hz

I = 350

I + 15 = 280

280I = 350(I + 15)

280I = 350I + 5250

280I - 350I = 5250

-70I = 5250

I = - 75cm

The length is - 75 cm

4 0
3 years ago
Suppose an automobile has 2000-joules of kinetic energy. when it moves at twice the speed, what will be its kinetic energy? what
NeX [460]

Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

K.E = \frac{1}{2}mv^2\\   ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\

using equation (1):

<u>K.Eₓ = 4 K.E</u>

For thrice speed:

vₓ = 3v

then,

K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\

using equation (1):

<u>K.Eₓ = 9 K.E</u>

6 0
3 years ago
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