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marta [7]
2 years ago
15

What is the missing angle of the triangle 48° 58°

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

74 degrees

Step-by-step explanation:

Start w/180 degrees. (The total measure of a triangle.) Then subtract 106 (the sum of the 2 known angles) from 180. We then get 74 degrees (The measure of the missing angle)

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62c + 86 = 32<br><br> A. -1.90<br><br> B. -.87<br><br> C. .35<br><br> D. 4.63
bearhunter [10]

Answer:<u>B</u>

62ç=32-86

62c=-54

C=0.87

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IM SORRY ME AGAIN ILL MARK BRAINLIST
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Answer:

The answer is letter D.

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1. $22.95 shirt, 7% (Indiana tax) total cost-
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I have to rewrite an equation so that y is a function of x. I think I'm solving for Y, because on my examples it has "y=". How d
vivado [14]

You do whatever you need to do to one side of the equation in order to have
only ' y ' left on that side, AND every time you do something to that side of
the equation, do exactly the same thing to the other side.

Here are three examples, out of the 9 answers you want handed to you:

<em>#16:</em>                                  <u>3x + 5y = 7</u>

Subtract  3x  from each side:      5y = -3x + 7

Divide each side by  5 :                <em>y = -3/5 x + 7/5</em>

======================================

<em>#17: </em>                                    <u>13 = 12x - 2y</u>

Add  2y  to each side:    2y + 13 = 12x

Subtract 13  from each side:  2y = 12x - 13

Divide each side by  2 :         <em> y = 6x - 13/2</em>

======================================

<em>#22:</em>                                <u>1/4 y + 3 = -5x</u>

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7 0
3 years ago
Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal. (Enter your answers as a comma-separated list.)
Gala2k [10]

Answer:

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

Step-by-step explanation:

Orthogonal vectors

Suppose we have two vectors:

v_{1} = (a,b,c)

v_{2} = (d,e,f)

Their dot product is:

(a,b,c).(d,e,f) = ad + be + cf

They are ortogonal is their dot product is 0.

Solving quadratic equations:

To solve this problem, we are going to need tosolve a quadratic equation.

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4a

Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal.

(4,x,-6)(2,x,x) = 8 + x^{2} - 6x

These vectors are going to be orthogonal if:

x^{2} -6x + 8 = 0

This is a quadratic equation, in which a = 1, b = -6, c = 8. So

\bigtriangleup = 6^{2} - 4*1*8 = 4

x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

3 0
3 years ago
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