Since the histogram is not symmetric, the grades shown in the math class below are not normally distributed.
<h3>When does a histogram represent a normal distribution?</h3>
A histogram represents a normal distribution if it symmetric.
In this problem, we have that:
- 57% of the grades are on the left tail.
- 25% of the grades are on the center.
- 18% are on the right tail.
Since the percentages at the tails are different, the histogram is not symmetric, and the grades shown in the math class below are not normally distributed.
More can be learned about the normal distribution at brainly.com/question/24537145
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Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
The inverse operation is a cubed root. It is a square root symbol with a small 3 to the left of the radical. The cubed root of x is a number, when cubed, gives x. For example, ![\sqrt[3]{8} =2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D2)
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Hey there! :)
Answer:
x = 21 units.
Step-by-step explanation:
Since we know Figure A is just Figure B scaled, we can set up a proportion:
Cross multiply to solve for x:
45 · x = 35 · 27
45x = 945
Divide both sides by 45:
x = 21 units.
Answer:
all of them
Step-by-step explanation:
all of them seem to have the same marks
but if u get the question wrong my next bet would be to go with only C because it has the marks on the sides if that makes sense
