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Simora [160]
2 years ago
10

Hello please help today is my birthday *

Mathematics
1 answer:
Rama09 [41]2 years ago
5 0

b. the range of the function is the set of all real numbers greater than 0.

that is false hope that helps

happy birthday

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If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term​
Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = a_{2} - a_{1} = a_{3} - a_{2}

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

a_{n} = a_{1} + (n - 1)d

a_{1} = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

a_{8} = 4 + (7 × 5) = 4 + 35 = 39

4 0
3 years ago
If 3x + 2y = 5, what is the value of the expression 6x + 4y - 7?
pickupchik [31]

Answer:

3

Step-by-step explanation:

x = 1

y = 1

6+4-7 = 3

6 0
3 years ago
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Solve: z-5=75<br><br> A:z=71<br> B:z=80<br> C:z=70<br> D:z=79
poizon [28]

B: z=80___________________________________

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3 years ago
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Melanie is 2 years older than Bill. Bill is 27 years old. After correctly carrying out the Solve step of the five-step problem-s
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it should just be 2 + 27 in order to find her age!

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3 years ago
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What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o
worty [1.4K]

Answer:

12

Step-by-step explanation:

The given geometric series is

\sum_{n = 1}^{ \infty} 12( { -  \frac{1}{9} })^{n - 1}

We want to determine the first term of this geometric series.

Recall that the explicit formula is

a_{n} = 12( { -  \frac{1}{9} })^{n - 1}

To find the first term, we put n=1 to get:

a_{1} = 12( { -  \frac{1}{9} })^{1 - 1}

This gives us:

a_{1} = 12( { -  \frac{1}{9} })^{0}

a_{1} = 12(1) = 12

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3 years ago
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