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Gre4nikov [31]
2 years ago
6

Which equation could represent the relationship shown in the scatter plot?

Mathematics
1 answer:
Nitella [24]2 years ago
5 0
Answer is A. y=3/4+10


Remember rise/run the line goes down 3 times and to the right 4 times. The 10 is the y-intercept basically where the dot/line starts
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9/20
NISA [10]

For this case we must find the solution of the following quadratic equation:

x ^ 2 + 5x + 7 = 0

Where:

a = 1\\b = 5\\c = 7

Then, the solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}

By definition we have:i ^ 2 = -1

x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0
3 years ago
Suppose a bag contains many marbles, 54% of which are purple. You draw 5 marbles from the bag with replacement.
dolphi86 [110]

Part A

Use the binomial probability distribution formula.

p = 0.54 = probability of getting a purple marble

n = 5 = sample size

x = 2 = number of purple we want to get

P(x) = \frac{n!}{x!(n-x)!}*p^x*(1-p)^{n-x}\\\\P(2) = \frac{5!}{2!(5-2)!}*0.54^2*(1-0.54)^{5-2}\\\\P(2) = 10*0.54^2*0.46^3\\\\P(2) = 0.283831776\\\\

The \frac{n!}{x!(n-x)!} portion is from the nCr combination formula. The exclamation marks indicate a factorial.

Alternatively, you could use Pascal's Triangle for that portion.

<h3>Answer: 0.283831776</h3>

This decimal value is exact. Round it however you need to.

============================================================

Part B

To find the expected value, aka the mean, we multiply the sample size and probability of getting a purple marble on any single selection.

n*p = 5*0.54 = 2.7

<h3>Answer: 2.7</h3>
6 0
2 years ago
Kyle received the following course grades for 10​ (three-credit) courses during his freshman​ year:
timofeeve [1]

Answer:

(a) The average grade point is 2.5.

(b) The relative frequency table is show below.

(c) The mean of the relative frequency distribution is 0.3333.

Step-by-step explanation:

The given data set is

4, 4, 4, 3, 3, 3, 1, 1, 1, 1

(a)

The average grade point is

Average=\frac{\sum x}{n}

Average=\frac{4+4+4+3+3+3+1+1+1+1}{10}

Average=2.5

Therefore the average grade point is 2.5.

(b)

\text{Relative frequency}=\frac{\text{Frequency of number}}{\text{Total frequency}}

The relative frequency table is show below:

x                 f                  Relative frequency

4                3                 \frac{3}{10}=0.3

3                3                 \frac{3}{10}=0.3

1                 4                 \frac{4}{10}=0.4

(c)

Mean of the relative frequency distribution is

Average=\frac{0.3+0.3+0.4}{3}

Average=0.3333

Therefore the mean of the relative frequency distribution is 0.3333.

4 0
3 years ago
Make x the subject of the formula x/a -b=c
horrorfan [7]

Answer:

x ÷ a - b = c

x a-b both side

x = c(a-b)

or

x = ca - bc

7 0
2 years ago
Read 2 more answers
A loan company charges $30 interest &lt;br /&gt;for a one month loan of $500. Find the annual interest they are charging ​
xz_007 [3.2K]

Answer:

$360

Step-by-step explanation:

If the company charges $30 for $500 in one month.

The interest they will be changing for a year = 30*12 = $360 interest.

It's just simple, multipling the the interest value by 12 to get it's annual interest value.

4 0
3 years ago
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