Answer:
D
Step-by-step explanation:
So we have the equation:
And we want to solve for x.
We can solve it by completing the square.
First, subtract 58 from both sides:
Divide the b term by 2 and square it:
So, add 9 to both sides:
On the left, the perfect square trinomial pattern. Add on the right. So:
Take the square root of both sides:
The square root of -49 is 7i:
Add 3 to both sides:
So, our answer is D.
And we're done!
Answer:
(x+1)(x-3i) (x+3i)
Step-by-step explanation:
x^3 + x^2 + 9x+9
We will use factor by grouping
Factor out x^2 from the first group and 9 from the second group
x^3 + x^2 + 9x+9
x^2( x+1) + 9(x+1)
Factor out (x+1)
(x+1) ((x^2+9)
Now factor x^2+9
x^2 -(3i)^2 = (x-3i) (x+3i)
Replacing this
(x+1)(x-3i) (x+3i)
Answer:
The inequality 14
Cecil had 14 boxes of lightbulbs when he started
I think not 100% sure
Step-by-step explanation:
Hope this helps :)
Check the picture below.
so the lunchbox is really a semi-circle with a radius of 3, sitting on top of a square of 6x6, with a lenght of 10.
the volume of the lunchbox then will be the area of the semi-circle and square times the length.
![\bf \left[ \stackrel{\textit{semi-circle's area}}{\frac{\pi 3^2}{2}}+\stackrel{\textit{square's area}}{(6\cdot 6)} \right]\stackrel{length}{10}\implies \left( \frac{9\pi }{2}+36\right)(10)](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5B%20%5Cstackrel%7B%5Ctextit%7Bsemi-circle%27s%20area%7D%7D%7B%5Cfrac%7B%5Cpi%203%5E2%7D%7B2%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bsquare%27s%20area%7D%7D%7B%286%5Ccdot%206%29%7D%20%5Cright%5D%5Cstackrel%7Blength%7D%7B10%7D%5Cimplies%20%5Cleft%28%20%20%5Cfrac%7B9%5Cpi%20%7D%7B2%7D%2B36%5Cright%29%2810%29)
Answer:
3.3000
Step-by-step explanation:
hope this helps
may i get braineist pls?
